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bazaltina [42]
3 years ago
15

Atoms with loosely held valence electrons have 1. high ionization energy and high electron affinity. 2. high ionization energy a

nd low electron affinity. 3. low ionization energy and high electron affinity. 4. low ionization energy and low electron affinity. 017
Chemistry
1 answer:
EastWind [94]3 years ago
3 0

Answer:

4

Explanation:

Ionization energy can be defined as the energy required for an atom to lose its valence electron to form an ion. Hence, it deals with how easily an atom would lose its electron and form an ion. As the valence electrons are lossless bound to the outermost shell, they can easily be lost without much problem or better still they can be lost easily. Hence, the energy change here is small and thus we can conclude that the ionization energy here is low.

The electron affinity works quite differently from the ionization energy. It deals with the way in which a neutral atom attracts an electron to form an ion. For an electron with loose valence electrons, the sure fact is that it does not really need these electrons. Hence, there is no need for an high electron affinity on its part. Thus, we conclude that the electron affinity is also low

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yulyashka [42]
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5 0
2 years ago
What is the pressure in atm exerted by 2.48 moles of a gas in a 250.0 mL container at 58 degrees celsius
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Since the question manages to include moles, pressure, volume, and temperature, then it is evident that in order to find the answer we will have to use the Ideal Gas Equation:  PV = nRT (where P = pressure; V = volume; n = number of moles; R = the Universal Constant [0.082 L·atm/mol·K]; and temperature.

First, in order to work out the questions, there is a need to convert the volume to Litres and the temperature to Kelvin based on the equation:
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             58 °C = 331 K

Also, based on the equation   P = nRT ÷ V

⇒         P  = (2.48 mol)(0.082 L · atm/mol · K)(331 K)  ÷  0.250 L
⇒         P  =  (67.31  L · atm) ÷ 0.250 L
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7 0
3 years ago
Coal power plants burn large amounts of coal, c(s), in an o 2 ​ (g) atmosphere to generate electricity. the chemical reaction re
charle [14.2K]
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From chemical reaction: n(C) . n(CO₂) = 1 : 1.
n(CO₂) = 8,33·10⁶ mol.
m(CO₂) = 8,33·10⁶ mol · 44 g/mol.
m(CO₂)  = 3,66·10⁸ = 3,66·10⁵ kg.
V(CO₂) = 3,66·10⁵ kg ÷ 1,98 kg/m³ = 1,84·10⁵ m³.
V(CO₂) = 1,84·10⁵ m³ · 1000 l/m³ = 1,84·10⁸ l.

6 0
3 years ago
which of the following parts of a circuit would be considered a load ? Justify your answer by explaining your choices • light •
QveST [7]
The answer to the question given above is letter A. Light
 
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>></span></span><span>Energy sources include batteries and generating stations
>>switch-</span><span>is used in electric circuits to allow the circuit to be turned on and off.</span>
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mina [271]

Answer:

A. Water

Explanation:

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7 0
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