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Nikolay [14]
3 years ago
10

Why are metals generally good conductors of electricity? 1. metals have more protons. 2. metals have strong bonding with other a

toms. 3. metals have free electrons in their outer shell?
Chemistry
2 answers:
Elodia [21]3 years ago
8 0
<span>Metals are good conductors of electricity because of the free electrons that is present in their outer shell that makes them good conductors of electricity. This is the most accepted fact that for any thing to transmit electricity by being a good conductor they need more free electrons in their outer shell</span>
Molodets [167]3 years ago
5 0
metal   have   free electrons  in  their   outer  shell  which  make  them  generally  good  conductors  of  electricity. Example  is  the  copper  which   is  used  for  electrical  wiring   since  is  a good  conductor  of  electricity.  copper  with   electronic configuration  of  (Ar)4s2 has  two  free  electrons  in  their  outer  most shell which  allow  it  to  conduct  electricity.
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What is the thermal energy needed to completely melt 9.60 mol of ice at 0.0 C
inysia [295]
The  thermal energy  needed to  completely  melt  9.60  mole  of ice  at  0.0 C  is    57.8   Kj

        Explanation
ice  melt  to  form   water

The molar  heat of fusion  for   water  is  6.02  Kj/mol
Thermal energy =  moles  x  molar  heat  of  fussion  for water

=9.6  mol  x6.02 kj/mol =57.8  Kj
4 0
3 years ago
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Ice melts to form water. And water freezes to form ice. Choose the TRUE statement about these changes.
Dmitrij [34]

Answer:

A. Both freezing and melting are physical changes.

Explanation:

Even if you were to freeze water, the molecules are still water molecules, and vise versa with melting it.

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What is "X" in the following reaction?
charle [14.2K]
X is the answer that we do not know yet!!:)
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3 years ago
when a solution of sodium chloride is added to a solution of copper(ii) nitrate, no precipitate is observed. Write the molexular
zhuklara [117]

Explanation:

1.

Cu(NO3)2 + 2NaCl(aq) --> CuCl2(aq) + 2NaNO3(aq)

2.

Cu(NO3)2 + 2NaOH(aq) --> Cu(OH)2(s) + 2NaNO3(aq)

A light blue precipitate of Cu(OH)2 is formed and NaNO3 in solution.

3.

Cu(NO3)2(aq) --> Cu2+(aq) + 2NO3^-2(aq)

2NaOH(aq) --> 2Na+(aq) + 2OH-(aq)

Cu2+(aq) + 2OH-(aq) --> Cu(OH)2(aq)

2Na+(aq) + 2NO3^-2(aq) --> 2NaNO3(aq)

4.

The reaction in both Questions 1 and 2 is called Double displacement reaction. A double-replacement reaction exchanges the cations and/or or the anions of two ionic compounds. A precipitation reaction is a double-replacement reaction in which one product is a solid precipitate (precipitated) while the other in solution.

Since the cation and anions in Qustion 1 were exchanged, the same was done for Question 2, hence the identity of the precipitate in Question 2 was got.

6 0
3 years ago
What is 57.048 rounded to three significant figures?
AnnyKZ [126]
57.0 is it rounded to three sig figs. You count three spaces then round from there, which would be the zero and you would round down because the four is there.
4 0
4 years ago
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