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Nikolay [14]
3 years ago
10

Why are metals generally good conductors of electricity? 1. metals have more protons. 2. metals have strong bonding with other a

toms. 3. metals have free electrons in their outer shell?
Chemistry
2 answers:
Elodia [21]3 years ago
8 0
<span>Metals are good conductors of electricity because of the free electrons that is present in their outer shell that makes them good conductors of electricity. This is the most accepted fact that for any thing to transmit electricity by being a good conductor they need more free electrons in their outer shell</span>
Molodets [167]3 years ago
5 0
metal   have   free electrons  in  their   outer  shell  which  make  them  generally  good  conductors  of  electricity. Example  is  the  copper  which   is  used  for  electrical  wiring   since  is  a good  conductor  of  electricity.  copper  with   electronic configuration  of  (Ar)4s2 has  two  free  electrons  in  their  outer  most shell which  allow  it  to  conduct  electricity.
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If one mole of PtCl2·3NH3 reacts with AgNO3 to produce one mole of AgCl(s), how can the formula PtCl2·3NH3 be re-written to show
Tresset [83]
The correct answer is b) [Pt(NH₃)₃Cl]Cl
Due to:
Chloride ion which is present outside the co-ordination sphere will react with AgNO₃ & since the reaction produces only one mole of AgCl so one Cl only outside the sphere and the formula is: [Pt(NH₃)₃Cl]Cl<span />
4 0
2 years ago
What is the [h3o ] for a solution of seawater at 25°c that has a ph of 8.3?
Kipish [7]
PH of solution at 25ºC = 8.3

[ H_3O^+] = 10 ^{-pH}

{H_3O^+] = 10 ^{-8.3}

[H_3O^+] = 5.011*10^{-9}  M

hope this helps!
6 0
3 years ago
How many kilojoules of energy would be required to heat a 225g block of aluminum from 23.0 C to 73.5 C?
gulaghasi [49]

Answer:

\boxed {\boxed {\sf 10.2 \ kJ}}

Explanation:

We are asked to find how many kilojoules of energy would be required to heat a block of aluminum.

We will use the following formula to calculate heat energy.

q=mc \Delta T

The mass (m) of the aluminum block is 225 grams and the specific heat (c) is 0.897 Joules per gram degree Celsius. The change in temperature (ΔT) is the difference between the final temperature and the initial temperature.

  • ΔT = final temperature - inital temperature

The aluminum block was heated from 23.0 °C to 73.5 °C.

  • ΔT= 73.5 °C - 23.0 °C = 50.5 °C

Now we know all three variables and can substitute them into the formula.

  • m= 225 g
  • c= 0.897 J/g° C
  • ΔT= 50.5 °C

q= (225 \ g )(0.897 \ J/g \textdegree C)(50.5 \textdegree C)

Multiply the first two numbers. The units of grams cancel.

q= (225 \ g  * 0.897 \ J/g \textdegree C)(50.5 \textdegree C)

q= (225   * 0.897 \ J / \textdegree C)(50.5 \textdegree C)

q= (201.825\ J / \textdegree C)(50.5 \textdegree C)

Multiply again. This time, the units of degrees Celsius cancel.

q= 201.825 \ J * 50.5

q= 10192.1625 \ J

The answer asks for the energy in kilojoules, so we must convert our answer. Remember that 1 kilojoule contains 1000 joules.

\frac { 1  \ kJ}{ 1000 \ J}

Multiply by the answer we found in Joules.

10192.1625 \ J * \frac{ 1 \ kJ}{ 1000 \ J}

10192.1625  * \frac{ 1 \ kJ}{ 1000 }

\frac {10192. 1625}{1000} \ kJ

10.1921625 \ kJ

The original values of mass, temperature, and specific heat all have 3 significant figures, so our answer must have the same. For the number we found, that is the tneths place. The 9 in the hundredth place tells us to round the 1 up to a 2.

10.2 \ kJ

Approximately <u>10.2 kilojoules</u> of energy would be required.

3 0
3 years ago
PLEASE HELP ME WITH THIS I WILL GIVE YOU POINTS
eduard

Answer:

1. a

2. c

3. b

4. f

5. d

6. e

Explanation:

7 0
3 years ago
What is a Control trial
AleksandrR [38]
It is a trial aimed to reduce bias during an experiment. An example would be a sugar pill, something that has no real effect so that the results of the true trial can accurately be compared. Its like a control group.
8 0
3 years ago
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