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Step2247 [10]
2 years ago
14

Lithium sulphate is used in some medicines and its presence in a medicine can be shown by two a combination of two tests a)expla

in how a flame test could help in this context
b) Describe how you would test a solution of the medicine for the presence of sulphate ions.
C) write a balanced chemical equation, including state symbols, for the reaction occurring in B)
Chemistry
1 answer:
shtirl [24]2 years ago
6 0

Answer:

A flame test could help by seeing what things it could catch on fire from or the things that could happen with acids etc. I would test the medicine by asking someone who has had it in their life, asking doctors or I would maybe use it myself maybe. (I don’t know about c, sooo sorry)

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The density of no2 in a 4.50 l tank at 760.0 torr and 25.0 °c is ________ g/l.
kap26 [50]
From  ideal  gas  equation   that   is   PV=nRT
n(number of  moles)=PV/RT
P=760 torr
V=4.50L
R(gas  constant =62.363667torr/l/mol
T=273 +273=298k
n  is   therefore   (760torr x4.50L) /62.36367 torr/L/mol  x298k  =0.184moles
the  molar  mass  of  NO2 is  46  therefore  density=  0.184  x  46=8.464g/l
7 0
2 years ago
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What atom has the largest atomic radius barium calcium magnesium radium
iogann1982 [59]

Answer:

Radium

Explanation:

It has the highest atomic number so it would have more shells, making it larger than the others.

6 0
3 years ago
What landform may form as a result of a volcanic eruption? A) delta B) floodplain C) moraine D) mountain
liubo4ka [24]
D) mountain

Hope this helps!
8 0
3 years ago
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An unknown compound with a molar mass of 223.94 g/mol consists of 32.18% c, 4.50% h, and 63.32% cl. find the molecular formula f
Dima020 [189]

The actual number of atoms of each element present in the molecule of the compound is represented by the formula known as molecular formula.

Molar mass of the unknown compound = 223.94 g/mol (given)

Mass of each element present in the unknown compound is determined as:

  • Mass of carbon, C:

\frac{32.18}{100}\times 223.94 = 72.06 g

  • Mass of hydrogen, H:

\frac{4.5}{100}\times 223.94 = 10.08 g

  • Mass of chlorine, Cl:

\frac{63.32}{100}\times 223.94 = 141.79 g

Now, the number of each element in the unknown compound is determined by the formula:

number of moles = \frac{given mass}{molar mass}

  • Number of moles of C:

number of moles = \frac{72.06}{12} = 6.005 mole\simeq 6 mole

  • Number of moles of H:

number of moles = \frac{10.08}{1} = 10.08 mole\simeq 10 mole

  • Number of moles of Cl

number of moles = \frac{141.79}{35.5} = 3.99 mole\simeq 4 mole

Dividing each mole with the smallest number of mole, to determine the empirical formula:

C_{\frac{6}{4}}H_{\frac{10}{4}}Cl_{\frac{10}{4}}

C_{1.5}H_{2.5}Cl_{1}

Multiplying with 2 to convert the numbers in formula into a whole number:

So, the empirical formula is C_{3}H_{5}Cl_{2}.

Empirical mass = 12\times 3+1\times 5+2\times 35.5 = 112 g/mol

In order to determine the molecular formula:

n = \frac{molar mass}{empirical mass}

n = \frac{223.94}{112} = 1.99 \simeq 2

So, the molecular formula is:

2\times C_{3}H_{5}Cl_{2} =  C_{6}H_{10}Cl_{4}

6 0
3 years ago
What is the best description of the energy stored in a stretched or compressed object.
oksian1 [2.3K]

Answer:

Elastic Potential Energy

4 0
3 years ago
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