Answer:
iron = 15000 kg 95% sulfuric acid = 27646.32 kg
Explanation:
The molar volume to a gas is 22.4 L, which means that a mole of a given gas at 0°C and 1 atm will have a volume os 22.4 L.
1 m3 - 1000 L
4870 m3 - x
x = 4870 * 1000 = 4.87 *10^6 L
1 mole - 22.4 L
y mole - 4.87 * 10^6 L
y =
= 2,17 *10^5 moles (if 100% of the H2 is used)
as 20% of it is lost, we need to know how much more we need to use.
80% - 2.17 * 10^5 moles
100% - z
z =
= 2,68*10^5 moles
so we would need 2.68*10^5 moles of iron and sulfuric acid.
1 mole of iron - 56 *10^-3 kg
2.68*10^5 moles - t
t= 2.68*56 *10^2 = 15000 kg
1 mole of sulfuric acid - 98 * 10^-3 kg
2.68*10^5 - u
u = 2.68*98 *10^2 = 26264 kg (if 100%)
95% - 26264 kg
100% - v
v =
= 27646.32 kg
Answer:
2
Explanation:
Mechanical Advantage (M.A) = Load/Effort....................................... (1)
Load = 10 N
Effort = 5 N
So substituting into equation (1), we have :
M.A = 10 N/5 N
= 2
CH₃-CH(-CH₃)-CH(-CH₃)-CH₃
2,3-dimethyl-1-butane
Explanation:
We have the following chemical reaction:
CH₂=C(-CH₃)-CH(-CH₃)-CH₃ + H₂ → CH₃-CH(-CH₃)-CH(-CH₃)-CH₃
So 2,3-dimethyl-1-butene will react with hydrogen to produce 2,3-dimethyl-1-butane.
Learn more about:
hydrogenation of double bonds in organic compounds
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1) Answer is: This ion is Br⁻ (bromine anion).
This ion has 36 electrons, because it has charge -1 (atom gain one electron), its atom has 35 electrons and 35 protons (atomic number 35). Element with atomic number 35 is bromine.
Electron configuration of ion with a charge of -1: ₃₅Br⁻ 1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d¹⁰ 4p⁶.
2) Answer is: chemical symbol of the noble gas is Kr (krypton).
Isoelectronic atom or ion has the same number of valence electrons. Krypton has 36 electron and 36 protons (atomic number 36).
The number of moles of oxygen (O2) required to completely react with 27.4 mol of H2 is 13.7 moles.
<h3>How to calculate number of moles?</h3>
The number of moles of a substance can be calculated using stoichiometry as follows:
The following balanced chemical equation is given as follows:
2H2 + O2 = 2H2O
According to this question, 2 moles of hydrogen gas (H2) reacts with 1 mole of oxygen gas (O2).
This means that 27.4 moles of hydrogen gas (H2) will react with 27.4/2 = 13.7moles of oxygen gas.
Therefore, the number of moles of oxygen (O2) required to completely react with 27.4 mol of H2 is 13.7 moles.
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