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3 years ago

Find the size of each of the unknown angles. Help me plz

Mathematics

1 answer:

saw5 [17]3 years ago

7 0

Answer:

2a+15 = 125(being alternate angle)

or,2a = 125-15

or,2a = 110

or,a = 110÷2

,a = 55

again,2a+15+b+30=180(Being co-interior angle)

or,2×55+15+b+30=180

or,110+15+30+b=180

or,155+b=180

or,b=180-155

Therfore,b=25

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-3y-5=10 Show your work please, thank you.

umka21 [38]

Answer:

-5

Step-by-step explanation:

-3y = 10 + 5

-3y = 15

y = - 5

3 0

3 years ago

Read 2 more answers

n a rural area, only about 30% of the wells that are drilled find adequate water at a depth of 100 feet or less. A local man cla

enyata [817]

Answer: the man's claim is true.

Step-by-step explanation:

Given that 30% of the well find water at a depth <=100 feet

P(X<=100) = 0.30

If the man's prediction work well the probability of finding well at less than 100 or equal should be high fwhen calculated from his results. So give 27 out of 80 wells

P(X<=100) = 27/80

P(X<=100) = 0.3375

Since 0.3375 > 0.3

The man's claim is true.

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3 years ago

A factory makes car batteries. The probability that a battery is defective is 1/14. If 400 batteries are tested, about how many

Rufina [12.5K]

Answer:

28.6, that is, about 29 are expected to be defective

Step-by-step explanation:

For each battery, there are only two possible outcomes. Either it is defective, or it is not. The probability of a battery being defective is independent of other betteries. So the binomial probability distribution is used to solve this question.

Binomial probability distribution

Probability of exactly x sucesses on n repeated trials, with p probability.

The expected value of the binomial distribution is:

$E(X) = np$

The probability that a battery is defective is 1/14.

This means that $p = \frac{1}{14}$

400 batteries.

This means that $n = 400$

How many are expected to be defective?

$E(X) = np = 400*\frac{1}{14} = 28.6$

28.6, that is, about 29 are expected to be defective

3 0

4 years ago

One pumpkin weighs 7 lb 12 oz. A second pumpkin with 10 pounds 4 ounces. A pumpkin weighs 2 pounds 9 ounces more than the second

Nesterboy [21]

Answer: 30 lbs, 13 oz

This converts to 493 ounces

===============================================================

Explanation:

Pumpkin A weighs 7 lb, 12 oz. Let's convert that to ounces only

1 lb = 16 oz

7 lbs = 112 oz (multiply both sides by 7)

7 lbs, 12 oz = 112 oz + 12 oz .... add 12 oz to both sides

7 lbs, 12 oz = 124 oz

Pumpkin A's weight of 7 lbs, 12 oz is the same as 124 oz

-----------

Do something similar for pumpkin B

1 lb = 16 oz

10 lbs = 160 oz

10 lbs, 4 oz = 160 oz + 4 oz

10 lbs, 4 oz = 164 oz

Pumpkin B weighs 164 oz

-----------

Let's convert the "2 lbs, 9 oz" to ounces only

1 lb = 16 oz

2 lbs = 32 oz

2 lbs, 9 oz = 32 oz + 9 oz

2 lbs, 9 oz = 41 oz

So pumpkin C is 41 ounces heavier compared to pumpkin B

The weight of pumpkin C is 164+41 = 205 ounces

----------

We have these three weights in ounces only

Pumpkin A = 124 oz
Pumpkin B = 164 oz
Pumpkin C = 205 oz

Adding those three ounces only weights leads to

124+164+205 = 493 ounces

The total weight of all three pumpkins is 493 ounces

Now let's convert back to the unit "pounds, ounces"

Divide that result over 16 since there are 16 ounces per pound

493/16 = 30.8125

Ignore the decimal portion. The 30 is the quotient which means 493-30*16 = 13 is the remainder.

In other words,

493/16 = 30 remainder 13

which leads to

493 ounces = 30 pounds, 13 ounces

--------------

As a check,

1 lb = 16 oz

30 lbs = 480 oz

30 lbs, 13 oz = 480 oz + 13 oz

30 lbs, 13 oz = 493 oz

The answer is confirmed.

8 0

3 years ago

Find the measure of the indicated angle to the nearest degree

Alisiya [41]

Answer:

The answer to your question is below

Step-by-step explanation:

14) sin Ф = 32/33

sin Ф = 0.9697

Ф = 75.86°

15) sin Ф = 16/36

sin Ф = 0.444

Ф = 26.39°

16) sin Ф = 29/36

sin Ф = 0.806

Ф = 53.66°

17) cos Ф = 11/34

cos Ф = 0.324

Ф = 71.12°

18) sin Ф = 21/40

sin Ф = 0.525

Ф = 31.67°

19) cos Ф = 6/14

cos Ф = 0.429

Ф = 64.62°

20) cos Ф = 38/39

cos Ф = 0.974

Ф = 13°

3 0

3 years ago

Find the size of each of the unknown angles. Help me plz​

Find the size of each of the unknown angles. Help me plz