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Travka [436]
3 years ago
6

Find the size of each of the unknown angles. Help me plz​

Mathematics
1 answer:
saw5 [17]3 years ago
7 0

Answer:

2a+15 = 125(being alternate angle)

or,2a = 125-15

or,2a = 110

or,a = 110÷2

,a = 55

again,2a+15+b+30=180(Being co-interior angle)

or,2×55+15+b+30=180

or,110+15+30+b=180

or,155+b=180

or,b=180-155

Therfore,b=25

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Answer:

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3 years ago
A pole that is 3.1m tall casts a shadow that is 1.29m long. At the same time, a nearby building casts a shadow that is 44.75m lo
Mkey [24]
Let b=height of building.   By similar triangles we can say:

b/44.75=3.1/1.29

b=44.75*3.1/1.29

b≈107.54

b≈108 meters  (to the nearest whole meter)
8 0
3 years ago
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What’s the answer I don’t understand
Scorpion4ik [409]
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5 0
3 years ago
Which equation represents the graph shown?<br> (Picture attached)
Maurinko [17]

Answer:

correct answer is option B

Step-by-step explanation:

as we know equation of line

       y = m x + c....................(1)

where c is the intercept

m is the slope

m = \dfrac{y_2-y_1}{x_2-x_1}

m = \dfrac{35-0}{1-0}

m = 35

putting value of m in equation (1)

we get

y = 35 x + c

from the graph we can clearly see that line is passing through (0,0) hence

0 = 35 (0)x + c

c = 0

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correct answer is option B

8 0
3 years ago
Two angles of a triangle measure 12º and 40°.
Sloan [31]

Answer:

12+40= 52

180-52=128

Step-by-step explanation:

Angles in a triangle add up to 180

so if two sides are given , they must be added and subtracted from 180.

which gives us 180-52=128

8 0
3 years ago
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