Answer:mathematical and map
Explanation:
"cg" is centigram, which is one-hundredth of a gram.
I will first convert from g to cg (multiply by 100), then from mL to L (multiply by 1000).

Three complete orders on each side of the m=0 order can be produced in addition to the m = 0 order.
The ruling separation is
d=1 / (470mm −1) = 2.1×10⁻³ mm
Diffraction lines occur at angles θ such that dsinθ=mλ, where λ is the wavelength and m is an integer.
Notice that for a given order, the line associated with a long wavelength is produced at a greater angle than the line associated with a shorter wavelength.
We take λ to be the longest wavelength in the visible spectrum (538nm) and find the greatest integer value of m such that θ is less than 90°.
That is, find the greatest integer value of m for which mλ<d.
since d / λ = 538×10⁻⁹m / 2.1×10 −6 m ≈ 3
that value is m=3.
There are three complete orders on each side of the m=0 order.
The second and third orders overlap.
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Answer: up to 4 other atoms.
Explanation:
- <em>Hybridization sp</em>³ means that the atom has 4 equal orbitals formed by the combination of 1 s and 3 p orbitals.
- Each of these sp³ orbitals is a place for a chemical bonding.
- Hence, since each orbital is able to bind a different atom, you conclude that <em>a central atom that is sp³ hydridized could bind up to 4 other atoms.</em>
This is precisely the case for carbon (C) atoms.
Carbon has atomic number 6. So its electron configuration is 1s² 2s²p².
The four electrons in the level 2, those shown in 2s² 2p², are in two different orbitals: two are in the orbital 2s and two are in the orbitals 2p.
This diagram shows how those 4 electrons fill the orbitals
The two 2s electrons have lower energy level than the 2px and 2 py electrons, but the difference is not too big.That is why one of the electrons in the 2s ortital can be promoted to the empty 2pz orbital, and you get 4 equal hydridized ortibals, so called sp³.
And that is why, carbon (C) ends up with 4 equal (hydridized) orbitals which can bind up to 4 different atoms, including other carbon atoms, and so, form long chains and, virtually, infinite compounds.
<span>A. Commercial cooking
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