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Blababa [14]
3 years ago
8

Calculate the pH of each solution at 25∘C

Chemistry
1 answer:
JulijaS [17]3 years ago
8 0

Answer: pH of HCl =5, HNO3 = 1,

NaOH = 9, KOH = 12

Explanation:

pH = -log [H+ ]

1. 1.0 x 10^-5 M HCl

pH = - log (1.0 x 10^-5)

= 5 - log 1 = 5

2. 0.1 M HNO3

pH = - log (1.0 x 10 ^ -1)

pH = 1 - log 1 = 1

3. 1.0 x 10^-5 NaOH

pOH = - log (1.0 x 10^-5)

pOH = 5 - log 1 = 5

pH + pOH = 14

Therefore , pH = 14 - 5 = 9

4. 0.01 M KOH

pOH = - log ( 1.0 x 10^ -2)

= 2 - log 1 = 2

pH + pOH = 14

Therefore, pH = 14 - 2 = 12

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Determine what type of compound is shown below:
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Many double-displacement reactions are enzyme-catalyzed via the "ping pong" mechanism, so called because the reactants appear to
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Answer:

<u>D. It will decrease by a factor of 4</u>

Explanation:

According to the question , the equation follows :

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Rate\ \alpha [A]^{a}[B]^{b}

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According to question, <u><em>doubling the concentration of the first reactant causes the rate to increase by a factor of 2 means,</em></u>

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Here [B] is uneffected means [B']=[B]

hence new rate =

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Divide equation (1) by (2) we , get

\frac{2r}{r}=\frac{[2A]^{2}[B]^{b}}{[A]^{a}[B]^{b}}

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2= 2^{a}\times 1^{b}

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2= 2^{a}

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1 + b = 3

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b = 2

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r=[A]^{a}[B]^{b}

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[B']=1/2[B]

Insert the value of [B'] in equation (3)

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r'=[A]^{1}(\frac{1}{2}[B])^{2}

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