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vampirchik [111]
3 years ago
14

Please help i will mark braniliest and 30 points

Mathematics
1 answer:
serious [3.7K]3 years ago
6 0

Answer:

D) x = -8

Step-by-step explanation:

All the values less than 7 are included in the number line. The graph on number line is shown in figure attached. In the options given, all values in Option A, B and C are greater than 7 so these cannot be included.

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2. Solve for x. SHOW YOUR WORK.
garik1379 [7]

Answer:

x=9

Step-by-step explanation:

The two labelled angles are equal, so we can construct an equation. Then, we solve the equation for x.

4x+2=7x-25\\2=3x-25\\3x=27\\x=9

First, we subtract 4x from both sides. Next, we add 25 to both sides. Finally, we divide both sides by 3.

8 0
3 years ago
What is equivalent to (x+y+2) (y+1)
ohaa [14]
Xy+x+y^2+3y+2 this is the answer
5 0
3 years ago
The equatorial diameter of a model of earth is 25.6 cm. What is the total surface area of the model​
Arisa [49]

Answer:

2059.7\,\,cm^2

Step-by-step explanation:

Diameter of a model of earth (D) = 25.6 cm

Radius of a model of earth (r) = \frac{D}{2}=\frac{25.6}{2}=12.8\,\,cm

Earth has the shape of a sphere.

Total surface area of a sphere = 4\pi r^2

Put \pi=\frac{22}{7}\,,\,r=12.8\,\,cm

So,

Total surface area of the model =4(\frac{22}{7})(12.8)^2=2059.7\,\,cm^2

7 0
3 years ago
Free Brainliest!!!!!!!!!!!OMG!!!!!!FREE BRAINLIEST
Alona [7]

Answer:

cool give it tome plz

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
when a cannonball is fired, the equation of its pathway can be modeled by h=-16t squared + 128t. find the time it will take for
Rashid [163]
At the time the cannonball reaches the ground, the vertical height of the cannonball from the ground is 0, i.e. h = 0.

Thus, the time it will take the cannonball to reach the ground is given by

-16t^2+128t=0 \\  \\ \Rightarrow t(-16t+128)=0 \\  \\ \Rightarrow t=0\ or\ -16t+128=0 \\  \\ \Rightarrow16t=128 \\  \\ \Rightarrow t= \frac{128}{16} =8

Therefore, it will take the cannonball 8 seconds to reach the ground.
5 0
4 years ago
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