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aivan3 [116]
3 years ago
8

2(x+4)-6 = 2(x-8)+1 plz show work because if I don't have it then I can't pass ​

Mathematics
1 answer:
Sedbober [7]3 years ago
7 0

Answer:

no solution

Step-by-step explanation:

Given

2(x + 4) - 6 = 2(x - 8) + 1 ← distribute and simplify both sides

2x + 8 - 6 = 2x - 16 + 1

2x + 2 = 2x - 15 ( subtract 2 from both sides )

2x = 2x - 17 ( subtract 2x from both sides )

0 = - 17 ← not possible

This indicates the equation has no solution

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What is the volume of the rectangular prism - i ready. 1/3 ft some of. The answers 1 1/9 feet3- 10 ft3 - 2/9 ft3 - 3 1/3 ft3
Kamila [148]

Answer:

3\frac{1}{3}\ ft^3

Step-by-step explanation:

A rectangular prism is a polyhedron with six rectangular faces. The volume of a prism is given by:

Volume = width * height * length

From the diagram, the rectangular prism is made up of cubes. Each cube is has a size of 1/3 ft by 1/3 ft.

The height of the prism is made up of 5 cubes. Height = 5 * 1/3 = 5/3 ft.

The length of the prism is made up of 3 cubes. length = 3 * 1/3 = 1 ft.

The width of the prism is made up of 2 cubes. Width = 2 * 1/3 = 2/3 ft.

The volume of the prism = width * height * length = 2/3 * 5/3 * 1 = 10/9 ft³ =  3\frac{1}{3}\ ft^3

6 0
3 years ago
Read 2 more answers
Combine and simplify the third set of terms 2+15a-2
Finger [1]
<span>2 + 15a - 2
= 15a (because 2 - 2 = 0)

hope it helps</span>
6 0
3 years ago
Tower one, a cube with a hexagonal prism measures 15.6cm. Tower two, a cube with a cylinder measures 18.3cm. Tower 3, a hexagona
lina2011 [118]

Answer:

Tower 4 = 23.9cm

Step-by-step explanation:

Given

Tower one = 15.6 cm

Tower two = 18.3 cm

Tower 3 = 13.9 cm.

Required:

Height of the 4th tower

Represent a cube by X; a cylinder by Y and a hexagonal prism by Z

Tower one, a cube with a hexagonal prism = X + Z = 15.6

Tower two, a cube with a cylinder = X + Y = 18.3

Tower 3, a hexagonal prism with a cylinder = Z + Y = 13.9

X + Z = 15.6 ----- Equation 1

X + Y = 18.3 ----- Equation 2

Z + Y = 13.9 ----- Equation 3

Subtract equation 1 from 2

(X + Y = 18.3) - (X + Z = 15.6)

X - X + Y - Z = 18.3 -15.6

Y - Z = 18.3 -15.6

Y - Z = 2.7 ---- Equation 4

Add Equation 4 to Equation 3

(Y - Z = 2.7) + (Z + Y = 13.9)

Y + Y - Z + Z = 2.7+ 13.9

2Y  = 2.7+ 13.9

2Y  = 16.6

Divide both sides by 2

\frac{2Y}{2}  = \frac{16.6}{2}

Y  = \frac{16.6}{2}

Y  = 8.3cm

Substitute Y  = 8.3cm in Equation 2 and 3

X + Y = 18.3 ----- Equation 2

X + 8.3 = 18.3

Subtract 8.3 from both sides

X + 8.3 - 8.3 = 18.3 - 8.3

X = 18.3 - 8.3

X = 10cm

Z + Y = 13.9 ----- Equation 3

Z + 8.3 = 13.9

Subtract 8.3 from both sides

Z + 8.3 - 8.3 = 13.9 - 8.3

Z = 13.9 - 8.3

Z = 5.6cm

So, we have that

X = 10cm

Y  = 8.3cm

Z = 5.6cm

The question states that the 4th tower is made up of the three shapes;

This implies that;

Tower 4 = X + Y + Z

Tower 4 = 10cm + 8.3cm + 5.6cm

Tower 4 = 23.9cm

The height of the 4th tower is 23.9cm

8 0
3 years ago
A new bridge structure requires triangles that are in a ratio of 1:1. If AC = 5x − 5 and EC = 3x + 9, find the distance between
Montano1993 [528]

Answer:

C. 60 ft

Step-by-step explanation:

If triangles ABC and EDC are in a 1:1 relation, they are congruent, and  

    AC = EC

5x - 5 = 3x + 9

    5x = 3x + 14

    2x = 14

      x = 7

AC = 5x + 5 = 5(7) - 5 = 35 - 5 = 30 ft

EC = 3x + 9 = 3(7) + 9 = 21 + 9 = 30 ft

Distance between top and bottom of bridge = AC + EC = 30 + 30 = 60 ft

5 0
3 years ago
Read 2 more answers
Experiments with repeated independent trials will be described by the binomial distribution if
bija089 [108]

Answer:

d. each trial has exactly two outcomes whose probabilities do not change

Step-by-step explanation:

A binomial experiment is one where there are exactly two outcomes for each trial and probability for getting success is constant in each trial.

In other words, each trial is independent of the other.

The trials need not be continuous nor time between trials to be constant.

Since trials are to be independent, each trial cannot influence the next.

Only option d is right.

d. each trial has exactly two outcomes whose probabilities do not change

Examples are tossing of coins, throwing dice, drawing cards or balls with replacement, etc

7 0
3 years ago
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