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2 years ago

What is the percent equation for 46% of 127?

Mathematics

1 answer:

Brut [27]2 years ago

3 0

Answer:

46% of 127 is 58.42

Step-by-step explanation:

46/100 = x/127

Cross multiply

46 × 127 = 100 × x

5,842 = 100x

Divide both sides by 100

58.42 = x

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Given △MON≅△PQR with MO=20 , MN=32 and PR=3x−10. Find the value of x.<br><br> show your work

aliya0001 [1]

Answer:

$x=14$

Step-by-step explanation:

we know that

If two figures are congruent, then its corresponding sides and its corresponding angles are congruent

In this problem

△MON≅△PQR

corresponding sides

MO≅PQ

MN≅PR

ON≅QR

corresponding angles

∠M≅∠P

∠O≅∠Q

∠N≅∠R

therefore

MN=PR

substitute the given values

$32=3x-10$

solve for x

$3x=32+10$

$3x=42$

$x=14$

3 0

3 years ago

In this problem we consider an equation in differential form Mdx+Ndy=0. (4x+2y)dx+(2x+8y)dy=0 Find My= 2 Nx= 2 If the problem is

zheka24 [161]

Answer:

$f(x,y)=2x^2+4y^2+2xy=C_1\\\\Where\\\\y(x)=\frac{1}{4} (-x\pm \sqrt{-7x^2+C_1} )$

Step-by-step explanation:

Let:

$M(x,y)=4x+2y\\\\and\\\\N(x,y)=2x+8y$

This is and exact equation, because:

$\frac{\partial M(x,y)}{\partial y} =2=\frac{\partial N}{\partial x}$

So, define f(x,y) such that:

$\frac{\partial f(x,y)}{\partial x} =M(x,y)\\\\and\\\\\frac{\partial f(x,y)}{\partial y} =N(x,y)$

The solution will be given by:

$f(x,y)=C_1$

Where C1 is an arbitrary constant

Integrate $\frac{\partial f(x,y)}{\partial x}$ with respect to x in order to find f(x,y):

$f(x,y)=\int\ {4x+2y} \, dx =2x^2+2xy+g(y)$

Where g(y) is an arbitrary function of y.

Differentiate f(x,y) with respect to y in order to find g(y):

$\frac{\partial f(x,y)}{\partial y} =2x+\frac{d g(y)}{dy}$

Substitute into $\frac{\partial f(x,y)}{\partial y} =N(x,y)$

$2x+\frac{dg(y)}{dy} =2x+8y\\\\Solve\hspace{3}for\hspace{3}\frac{dg(y)}{dy}\\\\\frac{dg(y)}{dy}=8y$

Integrate $\frac{dg(y)}{dy}$ with respect to y:

$g(y)=\int\ {8y} \, dy =4y^2$

Substitute g(y) into f(x,y):

$f(x,y)=2x^2+4y^2+2xy$

The solution is f(x,y)=C1

$f(x,y)=2x^2+4y^2+2xy=C_1$

Solving y using quadratic formula:

$y(x)=\frac{1}{4} (-x\pm \sqrt{-7x^2+C_1} )$

4 0

3 years ago

Suppose that two teams play a series of games that ends when one of them has won ???? games. Also suppose that each game played

Musya8 [376]

Answer:

(a) E(X) = -2p² + 2p + 2; d²/dp² E(X) at p = 1/2 is less than 0

(b) 6p⁴ - 12p³ + 3p² + 3p + 3; d²/dp² E(X) at p = 1/2 is less than 0

Step-by-step explanation:

(a) when i = 2, the expected number of played games will be:

E(X) = 2[p² + (1-p)²] + 3[2p² (1-p) + 2p(1-p)²] = 2[p²+1-2p+p²] + 3[2p²-2p³+2p(1-2p+p²)] = 2[2p²-2p+1] + 3[2p² - 2p³+2p-4p²+2p³] = 4p²-4p+2-6p²+6p = -2p²+2p+2.

If p = 1/2, then:

d²/dp² E(X) = d/dp (-4p + 2) = -4 which is less than 0. Therefore, the E(X) is maximized.

(b) when i = 3;

E(X) = 3[p³ + (1-p)³] + 4[3p³(1-p) + 3p(1-p)³] + 5[6p³(1-p)² + 6p²(1-p)³]

Simplification and rearrangement lead to:

E(X) = 6p⁴-12p³+3p²+3p+3

if p = 1/2, then:

d²/dp² E(X) at p = 1/2 = d/dp (24p³-36p²+6p+3) = 72p²-72p+6 = 72(1/2)² - 72(1/2) +6 = 18 - 36 +8 = -10

Therefore, E(X) is maximized.

6 0

3 years ago

15 points. Attached the question<br>

Vanyuwa [196]

Answer:

Step-by-step explanation:

(2x +1)/8 - (x-1)/3 = 5/24

multiple the 2x+1/8 by 3 and multiple (x-1)/3 by 8 then add them up

6x+3/24 - 8x-8/24 ➡ 6x-8x+11/24 = 5/24

➡ -2x+11 = 5

➡ -2x = 5-11

➡ x = 3

4 0

3 years ago

REUPLOAD!! (Worth 10 Points Each I Believe.) (please zoom / zoom out if needed to see question. (: )

irakobra [83]

I'm trying to help you in a easy way. Just multiply the numbers for part 1. And then add the numbers u multiplied from part 1 all together and you will have your answer for part 2. Lol don't report this because i am not good at multiplying so ye but this is what i would have done.<span />

5 0

3 years ago

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