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densk [106]
3 years ago
6

HELP PLSS ITS FOR MATHHH

Mathematics
1 answer:
Cerrena [4.2K]3 years ago
4 0

Answer:

Number 4

Step-by-step explanation:

I have done this quiz before, and that is what it looks like

I don't know if I am right, but good luck!

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Help please?!?!?!?!?!?!?!?!?!?!?!?!
zubka84 [21]

PEMDAS.

Parentheses

Exponents

Multiplication

Division

Addition

Subtraction

Lets apply that here.

72-[(3x2^3)+48]

So first we start with (3x2^3)

2^3=8

3*8=24

now we do 24+48 which equals 72

now we have 72-72 which equals zero.

So

72-[(3x2^3)+48] = 0

3 0
3 years ago
Read 2 more answers
Order the numbers from greatest to least.<br> 332 233 323
Hitman42 [59]

Answer:

Step-by-step explanation:

332 323 233

4 0
3 years ago
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48 x 56 in area model​
Alex787 [66]

Answer:

2688

Step-by-step explanation:

3 0
3 years ago
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A computer system uses passwords that are six characters, and each character is one of the 26 letters (a–z) or 10 integers (0–9)
Blababa [14]

First of all, since we have 36 characters available per spot (26 letters and 10 digits), and we have 6 spots, we have a total of

36^6

possible passwords.

Event A happens if the password starts with either a, e, i, o or u. If we fix the first character, we're left with 36 characters available for each of the remaining 5 spots, leading to a total of

5\cdot 36^5

possible passwords.

So, the probability of event A, computed as the ratio between "good" cases and all possible cases, is

\dfrac{5\cdot 36^5}{36^6}=\dfrac{5}{36}

Event B works exactly the same, since we're fixing the last spot, leaving 36 characters available for each of the first 5 spots. So, we have

P(A)=P(B)=\dfrac{5}{36}

As for the intersection, we want the first character to be a vowel, and the last character to be an even digits. There are 25 passwords satisfying this request:

axxxx0,\ axxxx2,\ axxxx4,\ axxxx6,\ axxxx8

exxxx0,\ exxxx2,\ exxxx4,\ exxxx6,\ exxxx8

ixxxx0,\ ixxxx2,\ ixxxx4,\ ixxxx6,\ ixxxx8

oaxxxx0,\ oxxxx2,\ oxxxx4,\ oxxxx6,\ oxxxx8

uxxxx0,\ uxxxx2,\ uxxxx4,\ uxxxx6,\ uxxxx8

Where x can be any of the 36 characters.

So, we have 25 cases with 4 vacant slots, leading to a probability of

P(A\cap B)=\dfrac{25\cdot 36^4}{36^6}=\dfrac{25}{1296}

Finally, you can compute the probability of the union using the formula

P(A\cup B)=P(A)+P(B)-P(A\cap B)

Since we already computed all these quantities.

7 0
3 years ago
E
NeTakaya

Answer:

$45 after the discount

Step-by-step explanation:

Set up a proportion.

     \frac{x}{50} = \frac{10}{100}      $50 is the total amount and make the 10% a decimal

x(100) = 50(10)

100 = 500

100 ÷ 500

x = 5     <-- We have to subtract this amount from the total

$50 - $5 = $45 <-- total after the discount

<u>Hope this helps!!</u>

4 0
3 years ago
Read 2 more answers
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