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Alex17521 [72]
3 years ago
5

assume that the weight of ripe watermelons grown at a particular farm are normally distributed witha mean of 20 pounds and a sta

ndard deviation of 1.4 pounds. determine the percent of watermelons that weigh between 18.48 pounds and 22.68 pounds
Mathematics
1 answer:
saul85 [17]3 years ago
4 0

Answer:

The answer is "78.25%"

Step-by-step explanation:

Given:

\mu =20\\\\\sigma=1.4

p(18.48

                                 =p(\frac{-1.52}{1.7}

                                 =p(Z

                                 =0.969258-0.1867329\\\\=0.7825251\\\\=78.25 \%

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hammer [34]

9514 1404 393

Answer:

  BC = 5

Step-by-step explanation:

Of course, this geometry program can tell you the length of BC.

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If you follow directions, you get a right triangle BCF that has leg lengths 3 and 4. The Pythagorean theorem then tells you the length of hypotenuse BC is ...

  BF = 4 -1 = 3

  FC = 4 -0 = 4

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7 0
3 years ago
If John owes 300 dollars and pays 50 a week what are the dependent and independent variables ​
podryga [215]
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7 0
3 years ago
PLEASE, I NEED HELP FOR A CLASS. The length of triangle base is 26. A line, which is parallel to the base divides the triangle i
sasho [114]

Answer:

DE=18.38

Step-by-step explanation:

It is given that the length of triangle base is 26 that is BC=26.

A line, which is parallel to the base divides the triangle into two equal area parts.

Therefore, from the given information, \frac{{\triangle}ADE}{ar ABC}=\frac{1}{2}.

Now, since it is given that A line, which is parallel to the base divides the triangle into two equal area parts, thus

\frac{ar ADE}{arABC}=\frac{1}{2}=\frac{(DE)^{2}}{(BC)^{2}}

⇒\frac{(DE)^{2}}{(BC)^{2}}=\frac{1}{2}

⇒\frac{(DE)^{2}}{(26)^{2}}=\frac{1}{2}

⇒(DE)^{2}=13{\times}26=338

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7 0
3 years ago
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mart [117]
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I’m not very familiar with the square roots method but I believe you try and isolate the term that is squared.

4 0
3 years ago
The side length of a square sticker is 3 inches. How many of these
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Answer:

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Step-by-step explanation:

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