Explain the difference between the three types of friction

1 answer:

8 0

Static Friction

It is the friction that exists between a stationary object and the surface on which it's resting.

Sliding friction

It is the resistance created by two objects sliding against each other.

Rolling friction:-

It is the force resisting the motion when a body rolls on a surface.

hope this helps x

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A train leaves the station heading south on the tracks. It takes 5 seconds to reach 50 miles per hour. It completes the entire 1

Musya8 [376]

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3 years ago

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Jet aircraft maintenance crews are required to wear protective earplugs. Members of a particular crew wear earplugs that reduce

Taya2010 [7]

Answer:

So the sound intensity level they would experience without the earplugs is 110.32dB.

Explanation:

Given data

Sound intensity by factor =215

Sound intensity level =87 dB

To find

Sound intensity level they would experience without the earplugs

Solution

First we need to find the new sound intensity level

$I_{n}=215(10^{\frac{87}{10} } )\\I_{n}=1.08*10^{11})$

The dB can be calculated as:

$dB=10log(I_{n})\\$

Substitute the given values

$dB=10log(1.08*10^{11})\\dB=110.32dB$

So the sound intensity level they would experience without the earplugs is 110.32dB.

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3 years ago

If ice has a density of.92g/cm, what is the volume of 1.8 kilograms of ice?

steposvetlana [31]

Given:
Density = .92 g / cm³
Volume = 1.8 kg
= (1.8 * 1000) grams
= 1800 grams
Now,
$Density (d) = \frac{Mass (m)}{volume(v)}$

$volume (v)= \frac{mass(m)}{density(d)}$

$volume (v)= \frac{1800}{.92}$

$volume (v)= 1956.521739$

$volume (v)= 1956.5~ cm^{3}$

So, the volume of 1.8 kg of ice is 1956.5 cm³

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