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3 years ago

What is the relationship between increase speed of a car and energy in a collision?

Physics

2 answers:

sweet [91]3 years ago

6 0

The relationship between a car and energy is that the car uses gas to produce speed within energy needs to be powered

Sonja [21]3 years ago

5 0

<h2>Answer:</h2>

<em>Hello, </em>

<h3><u>QUESTION)</u></h3><h3>✔We have : Ek = 1/2m x v² </h3>

In other words, when the speed doubles the collision energy of the car, or simply the kinetic energy, is multiplied by two.

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Determine the magnitude of the effective value of g⃗ at a latitude of 60 ∘ on the earth. assume the earth is a rotating sphere.

dezoksy [38]

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3 years ago

A centripetal force causes circular motion because it accelerates an object

MAVERICK [17]

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3 years ago

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A resistor uses 100 w of power when connected to 120 v emf. What is the current through the same resistor when connected to a 22

cricket20 [7]

Answer:

Explanation:

Let the resistance of resistor be R .

Power of resistor V² / R , where V is potential applied .

V² / R = 100

120² / R = 100

R = 120² / 100

= 144 ohm .

Now potential diff applied = 220 V

current = potential diff / resistance

= 220 / 144

= 1.53 A approx .

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3 years ago

Which statement about coal is true? When burned, coal produces pollutants that are released into the air. Coal will always stay

Svetllana [295]

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3 years ago

A uniform rod rotates in a horizontal plane about a vertical axis through one end. The rod is 3.46 m long, weighs 12.8 N, and ro

Mkey [24]

Answer:

a. Rotational inertia: 5.21kgm²

b. Magnitude of it's angular momentum: 123.32kgm²/s

Explanation:

Length of the rod = 3.46m

Weight of the rod = 12.8 N

Angular velocity of the rod= 226 rev/min

a. Rotational Inertia (I) about its axis

The formula for rotational inertia =

I = (1/12×m×L²) + m × ( L ÷ 2)²

Where L = length of the rod

m = mass of the rod

Mass of the rod is calculated by dividing the weight of the rod with the acceleration due to gravity.

Acceleration due to gravity = 9.81m/s²

Mass of the rod = 12.8N/ 9.81m/s²

Mass of the rod = 1.305kg

Rotational Inertia =

(1/12× 1.305 × 3.46²)+ 1.305 ( 3.46÷2)²

Rotational Inertia = 1.3019115 + 3.9057345

Rotational Inertia = 5.207646kgm²

Approximately = 5.21kgm²

b. The magnitude of the rod's angular momentum about the rotational axis is calculated as

Rotational Inertia about its axis × angular speed of the rod.

Angular speed of the rod is calculated as= (Angular velocity of the rod × 2π)/60

= (226×2π) /60

= 23.67 rad/s

Rotational Inertia = 5.21kgm²

The magnitude of the rod's angular momentum about the rotational axis

= 5.21kgm²× 23.67 rad/s

= 123.3207kgm²/s

Approximately = 123.32kgm²/s

7 0

3 years ago