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o-na [289]
3 years ago
14

How many grams are in 1.5moles of calcium

Chemistry
1 answer:
Trava [24]3 years ago
6 0

Answer: 60.117 g

Explanation: 1.5 mol Ca = \frac{40.078g/mol}{1mol} multiply and quit all "mol" and you get the grams

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How can energy from the Sun be used to heat water? What
worty [1.4K]

Answer:

Water is heated as it travels through flat, glazed panels known as solar collectors, which are normally situated on the roof of the building. The heated water is then stored in an insulated storage tank.

4 0
3 years ago
A mixture of 0.600 mol of bromine and 1.600 mol of iodine is placed into a rigid 1.000-L container at 350°C. Br2(g) + I2(g) 2IBr
blagie [28]

Answer:

The answer to your question is K = 1.48

Explanation:

Balanced chemical reaction

                   Br₂   +   I₂    ⇒    2IBr

Process

1.- Calculate the concentration of each of the reactants

[Br₂] = 0.6 mol  / 1  L

        = 0.6 M

[I₂] = 1.6 mol / 1 L

     = 1.6 M

[IBr] = 1.19 M

2.- Write the equation of the Equilibrium constant

      K = [IBr]² / [Br₂][I₂]

-Substitution

      K = [1.19]² / [0.6][1.6]

- Simplification

      K = 1.4161 / 0.96

- Result

      K = 1.48

5 0
3 years ago
How many grams of naoh are needed to prepare 500 ml of 0.125 m naoh?
Romashka-Z-Leto [24]

First let us calculate for the number of moles needed:

moles NaOH = 0.125 M * 0.500 L = 0.0625 mol

 

The molar mass of NaOH is 40 g/mol, hence the mass is:

mass NaOH = 0.0625 mol * 40 g/mol

<span>mass NaOH = 2.5 grams</span>

6 0
3 years ago
Explain the difference between passive transport and active transport
garri49 [273]
Energy is not required in passive transport,<span> and in active transport energy is required.
</span><span>In active transport, the molecules move against the concentration gradient that is from low to high concentration.
In passive transport, the molecules move with the concentration gradient thatis from high to low concentration.</span>
6 0
4 years ago
Convert 835g Ar to liters of Argon gas. Please Help!!!
Feliz [49]
 835 g Ar  to  liters of Argon  gas  is  calculated as    follows

find  the  moles of Ar =  mass/molar mass

= 835g /39.95  g/mol  =  20.9  moles

At  STP   1mole of  ideal  gas =  22.4 L,  what  about  20.9 moles

= 20.9 moles/1mole x 22.4 L =468.16 L  of Argon
5 0
3 years ago
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