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o-na [289]
3 years ago
14

How many grams are in 1.5moles of calcium

Chemistry
1 answer:
Trava [24]3 years ago
6 0

Answer: 60.117 g

Explanation: 1.5 mol Ca = \frac{40.078g/mol}{1mol} multiply and quit all "mol" and you get the grams

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What does genetic modification produce
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Genetic modification or GMOs can change foods. It's typically used to preserve foods, enlargen foods or create seedless grapes

Explanation:

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An adult mosquitoes lifespan is about 16 days how many minutes is that
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The answer is 23, 040 minutes. To solve this you can start by changing days in to hours. We know that there are 24 hours in a day. To find how many hours are in 16 days you multiply 24 by 16 which is 384. Next you must find out how many minutes are in 384 hours. we know there are 60 minutes per hour. To find how many minutes are in 384 hours, you multiply 384 by 60. To this you get 23, 040 which is your answer.
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A sample originally contains 24 grams of a radioactive isotope. After 18 days, 18.8 grams of the isotope remain in the sample. W
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2 years ago
A Cu/Cu2 concentration cell has a voltage of 0.22 V at 25 o C. The concentration of Cu2 in one of the half-cells is 1.5 x 10-3 M
Olin [163]

Answer:

The concentration is  [Cu^{2+}]_a  = 10^{-10.269}  

Explanation:

From the question we are told that

    The voltage of the cell is  E =  0.22 \  V

   

   

Generally the reaction at the cathode is  

  Cu^{2+} _{(aq)} + 2e^{-} \to  Cu_{s} the half cell voltage is  V_c =  0.337 V

Generally the reaction at the anode is    

   Cu _{(s)} \to Cu^{2+} _{(aq)} +  2e^{-}  the half cell voltage is  V_a = -0.337 V

Gnerally the reaction of the cell is  

    Cu_{(s)} + Cu^{2+} _{(aq)} \to Cu^{2+}_{(aq)} +  Cu_{(s)}

At initial the voltage is  V  =  0 V

Generally the voltage of the cell at 25°C is  

       E =  V  - \frac{0.0591}{n} log \frac{[Cu^{2+}] _a}{[Cu^{2+}]_c}

Here n is number of  of electron and it is 2

So from the question we are told that one cell has a concentration 1.5 x 10-3 M

Let assume it is  [Cu^{2+}]_c

So

      0.22=  0  - \frac{0.0591}{2} log \frac{[Cu^{2+}] _a}{  1.5 * 10^{-3} }

=>    -7.445 =     log \frac{[Cu^{2+}] _a}{  1.5 * 10^{-3} }

=>  -7.445 =     log [Cu^{2+}_a] - log [1.5*10^{-3}]

=>    -7.445  + log [1.5*10^{-3} =     log [Cu^{2+}_a]

=>    -7.445  - 2.824 =     log [Cu^{2+}_a]

Taking the antilog

=>    [Cu^{2+}]_a  = 10^{-10.269}    

=>     [Cu^{2+}]_a  = 5.38 *10^{-11} \  M  

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3 years ago
Marble is made from limestone under the influence of heat and pressure. The chemical formula for limestone or marble
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Answer:

what is the gas that is produced.

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