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cluponka [151]
3 years ago
12

How many grams of naoh are needed to prepare 500 ml of 0.125 m naoh?

Chemistry
1 answer:
Romashka-Z-Leto [24]3 years ago
6 0

First let us calculate for the number of moles needed:

moles NaOH = 0.125 M * 0.500 L = 0.0625 mol

 

The molar mass of NaOH is 40 g/mol, hence the mass is:

mass NaOH = 0.0625 mol * 40 g/mol

<span>mass NaOH = 2.5 grams</span>

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What is the atomic number of arsenic (As)?<br> O A. 33<br> O B. 15<br> C. 75<br> D. 4<br> SUB
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5 0
2 years ago
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What volume of so2 is produced at 325 k and 1.35 atm when 15.0 grams of hcl reacts with excess k2so3?
vova2212 [387]
The volume of SO2 produced at 325k   is calculated as  below

calculate  the moles of SO2 produced  which  is calculated as follows

write the  reacting equation
K2SO3 +2 HCl = 2KCl +H2O+ SO2

find the   moles  of  HCl  used
=mass/molar mass = 15g/ 36.5 g/mol =0.411 moles

by  use of mole ratio between  HCl to  SO2  which is  2:1 the moles of SO2 is therefore = 0.411 /2 =0.206  moles  of SO2

use the idea  gas  equation  to calculate the volume SO2
that is V=nRT/P  
where  n=0.206  moles
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V=(0.206 moles x  0.082 L.atm/mol.k x325 k)/1.35 atm = 4.07 L of SO2

3 0
2 years ago
An ideal gaseous reaction (which is a hypothetical gaseous reaction that conforms to the laws governing gas behavior) occurs at
lana [24]

Answer:

ΔU = −55.45 kJ

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ΔU = Q + W

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We are given;

Q = 74.6 kJ

But Q will be negative since heat is released

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We are given;

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Now,

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W = - 3546375(0.0028 - 0.0082)

W = 19.15 KJ

Thus;

ΔU = Q + W

ΔU = -74.6 kJ + 19.15 KJ =

ΔU = −55.45 kJ

6 0
2 years ago
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