When the first reaction equation is:
AgI(S) ↔ Ag+(Aq) + I-(Aq)
So, the Ksp expression = [Ag+][I-]
∴Ksp = [Ag+][I-] = 8.3 x 10^-17
Then the second reaction equation is:
Ag+(aq) + 2NH3(aq) ↔ Ag(NH3)2+
So, Kf expression = [Ag(NH3)2+] / [Ag+] [NH3]^2
∴Kf = [Ag(NH3)2+] /[Ag+] [NH3]^2 = 1.7 x 10^7
by combining the two equations and solve for Ag+:
and by using ICE table:
AgI(aq) + 2NH3 ↔ Ag(NH3)2+ + I-
initial 2.5 0 0
change -2X +X +X
Equ (2.5-2X) X X
so K = [Ag(NH3)2+] [I-] / [NH3]^2
Kf * Ksp = X^2 / (2.5-2X)
8.3 x 10^-17 * 1.7 x10^7 = X^2 / (2.5-2X) by solving for X
∴ X = 5.9 x 10^-5
∴ the solubility of AgI = X = 5.9 x 10^-5 M
25
There are 25 protons in an atom of Mn-51 even if the atom has a charge of +1. The proton number also defines the atomic number of an atom.
Explanation:
The proton number of the atoms of an element never change without changing the type of atom/ element. Therefore, in other words, the atomic number (which is equivalent to proton number) remains the same across all isotopes of an element. Even when the atoms lose some electrons, the proton number remains the same.
Manganese (Mn) has atomic number 25. Meaning it has 25 protons. This proton number remains the same even if the Mn atoms are charged.
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The element X is Copper.
Explanation :
Reactive metals from 3d transition series like Cu are very reactive because their standard reduction potential values are low.
Hence, when treated with a acid it tends to liberate hydrogen gas.
Also, because of its low reduction potential value, it can easily displace lead and tin from their salt solutions.
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