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Nostrana [21]
3 years ago
10

Convert 835g Ar to liters of Argon gas. Please Help!!!

Chemistry
1 answer:
Feliz [49]3 years ago
5 0
 835 g Ar  to  liters of Argon  gas  is  calculated as    follows

find  the  moles of Ar =  mass/molar mass

= 835g /39.95  g/mol  =  20.9  moles

At  STP   1mole of  ideal  gas =  22.4 L,  what  about  20.9 moles

= 20.9 moles/1mole x 22.4 L =468.16 L  of Argon
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Find the pressure of a gas if the volume is 2.00 L, the temperature is 310 Kelvin and
kipiarov [429]

Answer:

25.42 atm

Explanation:

Data Given:

Volume of a gas ( V )= 2.00 L

temperature of a gas ( T ) =  310 K

number of moles (n) = 2​ mol

Pressure of a gas ( P ) = to be find

Solution:

Formula to be used

              PV= nRT

Rearrange the above formula

              P = nRT / V . . . . . . . . . . (1)

Where R is ideal gas constant

R = 0.08205 L atm mol⁻¹ K⁻¹

Put values in equation 1

                 P = nRT / V

                  P = 2 mol x 0.08205 L atm mol⁻¹ K⁻¹ x 310 k / 2 L

                  P = 50.84 L atm / 2 L

                  P = 25.42 atm

P ressure of gas (P) will be = 25.42 atm

7 0
4 years ago
Given the different molecular weights, dipole moments, and molecular shapes, why are their molar volumes nearly the same?
Marina CMI [18]

Answer:

option d

Explanation:

Molecular sizes of gaseous molecules are very less. Volume occupied by the all the molecules of the gases are very less or negligible as compared to the container in which it is kept. Therefore, most of the volume occupied by gaseous molecules are negligible.

Volume occupied by the gaseous molecules are actually the volume of the container and its does not depend upon the amount, molecular mass or dipole moment of the gaseous molecules.

Therefore, the correct option is d ‘Because most of the volume occupied by the substance is empty space.’

8 0
4 years ago
You are given 100 g of a compound. The compound is composed of 37% hydrogen and 63% oxygen. How many grams of hydrogen are prese
Reil [10]
B is the best answer
4 0
3 years ago
Match each transition metal ion with its condensed ground-state electron configuration. A [Ar]3d2 B [Ar]4s23d3 C [Kr]4d10 D [Xe]
madreJ [45]

Answer:

Mn^{2+} : - F . [Ar]3d^{5}

Hg^{2+} : - G. [Xe]4f^{14}5d^{10}

La^{3+} : - D. [Xe]

Fe^{3+} : - F. [Ar]3d^{5}

Ag^{+} : - C. [Kr]4d^{10}

Co^{3+} : - E. [Ar]3d^{6}

Explanation:

The electronic configuration of the element Mn is:-

[Ar]3d^{5}4s^2

For, Mn^{2+}, 2 electrons are lost, thus the configuration is:-

[Ar]3d^{5}

The electronic configuration of the element Hg is:-

[Xe]4f^{14}5d^{10}6s^2

For, Hg^{2+}, 2 electrons are lost, thus the configuration is:-

[Xe]4f^{14}5d^{10}

The electronic configuration of the element La is:-

[Xe]5d^{1}6s^2

For, La^{3+}, 3 electrons are lost, thus the configuration is:-

[Xe]

The electronic configuration of the element Fe is:-

[Ar]3d^{6}4s^2

For, Fe^{3+}, 3 electrons are lost, thus the configuration is:-

[Ar]3d^{5}

The electronic configuration of the element Ag is:-

[Kr]4d^{10}5s^1

For, Ag^{+}, 1 electron is lost, thus the configuration is:-

[Kr]4d^{10}

The electronic configuration of the element Co is:-

[Ar]3d^{7}4s^2

For, Co^{3+}, 3 electrons are lost, thus the configuration is:-

[Ar]3d^{6}

7 0
3 years ago
When Iodine-131 emits a β particle (beta particle), what nuclide is produced? *
k0ka [10]

When Iodine-131 emits a β particle will produce Xe-131

<h3>Further explanation </h3>

Radioactivity is the process of unstable isotopes to stable isotopes by decay, by emitting certain particles,  

  • alpha α particles ₂He⁴
  • beta β ₋₁e⁰ particles
  • gamma particles ₀γ⁰
  • positron particles ₁e⁰
  • neutron ₀n¹

So for reaction Iodine-131 :

\tt _{53}^{131}I\rightarrow _{-1}^0\beta +_{54}^{131}Xe

5 0
3 years ago
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