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Amanda [17]
3 years ago
11

How do I solve this?

Mathematics
1 answer:
Rus_ich [418]3 years ago
7 0

Answer:

I think the answer is m=3

Step-by-step explanation:

Hope this helps :D

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3(8 - x) = 7x - 6<br> I need help
Whitepunk [10]
The answer to your question is 3
8 0
3 years ago
Read 2 more answers
Lines l1 and l2 are parallel and l3 is a transversal.
enot [183]

Answer:

C. m∠1 = m∠4

Step-by-step explanation:

A. m∠2 + m∠4 = 180°

∠2 and ∠4 are vertically opp. angles which means m∠2 = m∠4.

Hence, it's a <u>false</u> statement.

B. m∠2 + m∠3 = 180°

∠2 and ∠3 are corresponding angles which means m∠2 = m∠3.

It's a <u>false</u> statement.

C. m∠1 = m∠4

∠1 and ∠4 are another pair of corresponding angles which clearly states that m∠1 = m∠4.

Therefore, it's a <u>true</u> statement.

D. m∠1 = 90°

As clearly visible in the diagram;

It's a <u>false</u> statement.

5 0
3 years ago
PLEASE HELP WITH PART B
Hoochie [10]
I don’t really get what exactly you need help with, maybe put a picture?
3 0
3 years ago
Pulse rates (in beats per minute) were collected on a sample of 36 men. The five number summary for the data is as follows: Lo:
algol13

Answer:

27 men had a pulse rate between 56 & 100.  

Step-by-step explanation:

We are given the following in the question:

Sample size, n = 36

Five number summary:

Lowest value: 56

Lower Quartile: 71

Median: 80

Upper Quartile: 100

Highest value: 140

We have to find the number of men that had a pulse rate between 56 & 100.

56 is the lowest value of data and 100 is the third quartile of data.

Now, the third quartile give 75 percentile of data, thus, 75% of data lies between lowest value and the third quartile.

Thus, 75% of men have a pulse rate between 56 & 100.

Number of men that had a pulse rate between 56 & 100 =

75\% \times n\\\\=\dfrac{75}{100}\times 36 = 27

Thus, 27 men had a pulse rate between 56 & 100.

6 0
3 years ago
Find the volume of the cone. Round your answer to the nearest tenth.
Roman55 [17]

Answer:

<u>65.4 cubic inches</u>

Step-by-step explanation:

Formula for the volume of a cone :

<u><em>Volume (cone) = 1/3πr²h</em></u>

<u><em /></u>

=============================================================

Given :

⇒ diameter = 5 in. → radius = <u>2.5 in.</u>

⇒ height = <u>10 in.</u>

<u />

===========================================================

Solving :

⇒ Volume (cone) = 1/3 × π × (2.5)² × 10

⇒ Volume (cone) = 62.5π/3

⇒ Volume (cone) = <u>65.4 cubic inches</u>

8 0
2 years ago
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