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3 years ago

Calculate the molarity of a solution prepared by dissolving 6.87 grams of AgNO3 in enough water to make 2.50 liters of solution.

Chemistry

1 answer:

beks73 [17]3 years ago

4 0

Answer:

The molarity of the solution is 0.016 $\frac{moles}{L}$

Explanation:

Molar concentration is a measure of the concentration of a solute in a solution.

Molarity (M) or Molar Concentration is the number of moles of solute that are dissolved in a certain volume.

Molarity is determined by dividing the moles of the solute by the volume of the solution:

$Molarity=\frac{number of moles of solute}{volume}$

Molarity is expressed in units $\frac{moles}{liter}$ .

Being 169.87 g / mole the molar mass of AgNO₃, then you can apply the following rule of three: if 169.87 grams are contained in 1 mole, 6.87 grams are contained in how many moles?

$amount of moles=\frac{6.87 grams*1 mole}{169.87 grams}$

amount of moles= 0.04 moles

Then:

number of moles of solute: 0.04 moles
volume: 2.50 L

Replacing:

$Molarity=\frac{0.04 moles}{2.50 L}$

Solving:

Molarity= 0.016 $\frac{moles}{L}$

The molarity of the solution is 0.016 $\frac{moles}{L}$

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