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3 years ago

Write down the compounds that does not have an alpha hydrogen.

Chemistry

1 answer:

Yuliya22 [10]3 years ago

6 0

Answer:

This question appears incomplete

Explanation:

However, an alpha hydrogen is the hydrogen that is found on the alpha, α-carbon in an organic molecule. Alpha carbon is referred to the first carbon that is attached to a functional group. Generally, compounds that do not have alpha carbon do not have alpha hydrogen. For example, first member of all functional groups do not usually have alpha carbon and hence do not have alpha hydrogen.

Also, Alkanes, alkenes and alkynes do not have also

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Please help Will give brainliest A - 1 B - 2 C - 3 D - 4 E - 5

Basile [38]

Answer:

B-2

Explanation:

In the graph you can so that two of the shapes ae fully black, that means that they are color blind, the half colored ones means they are a carrier but they aren't color blind. So two males in the offspring are color blind.

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2 years ago

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Which of the following best demonstrates kinetic energy?

Novay_Z [31]

Hey there!

Kinetic energy means that something is in motion.

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3 years ago

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How many particles are present in 12.47 grams of NaCl

liq [111]

Answer:

1.26*10²³ particles are present in 12.47 grams of NaCl

Explanation:

Avogadro's Number or Avogadro's Constant is called the number of particles that make up a substance (usually atoms or molecules) and that can be found in the amount of one mole of said substance. Its value is 6.023 * 10²³ particles per mole. The Avogadro number applies to any substance.

So, first of all you must know the amount of moles that represent 12.47 grams of NaCl. For that it is necessary to know the molar mass.

You know:

Na: 23 g/mole
Cl: 35.45 g/mole

So the molar mass of NaCl is: 23 g/mole + 35.45 g/mole= 58.45 g/mole

Now you apply a rule of three as follows: if 58.45 grams are present in 1 mole of NaCl, 12.47 grams in how many moles will they be?

$moles=\frac{12.47 grams*1 mole}{58.45 grams}$

moles= 0.21

You apply a rule of three again, knowing Avogadro's number: if in 1 mole of NaCl there are 6,023 * 10²³ particles, in 0.21 moles how many particles are there?

$number of particles=\frac{0.21 moles*6.023*10^{23} }{1 mole}$

number of particles= 1.26*10²³

1.26*10²³ particles are present in 12.47 grams of NaCl

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3 years ago

A reaction produces 92.50 g FeSO4. How many grams of CuSO4 are necessary for this to occur?

xxMikexx [17]

Fe+CuSO4⟶Cu+FeSO4

Given that

FeSO4 = 92.50 g

Number of moles = amount in g / molar mass

=92.50 g / 151.908 g/mol

=0.609 moles FeSO4

Now calculate the moles of CuSO4 as follows:

0.609 moles FeSO4 * 1 mole CuSO4 /1 mole FeSO4

= 0.609 moles CuSO4

Amount in g = number of moles * molar mass

= 0.609 moles CuSO4 * 159.609 g/mol

= 97.19 g CuSO4

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3 years ago

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Which describes the molecule below?

12345 [234]

Answer:

Option D. A liquid with three unsaturated fatty acids.

Explanation:

A careful observation of the molecule given in question shows that the molecule is unsaturated as all three fatty acid that make up the compound contain double.

Double is a characteristic property of unsaturated compound.

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3 years ago