The theoretical mass of silver that will be produced is calculated as follows
write the reaction equation
Cu + 2Ag(No3) ---> 2Ag + Cu(NO3)2
calculated the moles of each reagent
moles =mass/molar mass
Cu = 6.51g/63.5g/mol= 0.103 moles
Ag(NO3)2 = 28.4 g/169.87g/mol = 0.167 moles
Cu is the limiting reagent therefore the moles Ag= 2 x0.167 = 0.334 moles
mass = moles xmolar mass
0.334mol x 107.87g/mol = 36.02 grams
Answer: 1
Explanation: coarse adjustment
A: Some ice will turn into liquid water.
Answer:
0.924 g
Explanation:
The following data were obtained from the question:
Volume of CO2 at RTP = 0.50 dm³
Mass of CO2 =?
Next, we shall determine the number of mole of CO2 that occupied 0.50 dm³ at RTP (room temperature and pressure). This can be obtained as follow:
1 mole of gas = 24 dm³ at RTP
Thus,
1 mole of CO2 occupies 24 dm³ at RTP.
Therefore, Xmol of CO2 will occupy 0.50 dm³ at RTP i.e
Xmol of CO2 = 0.5 /24
Xmol of CO2 = 0.021 mole
Thus, 0.021 mole of CO2 occupied 0.5 dm³ at RTP.
Finally, we shall determine the mass of CO2 as follow:
Mole of CO2 = 0.021 mole
Molar mass of CO2 = 12 + (2×16) = 13 + 32 = 44 g/mol
Mass of CO2 =?
Mole = mass /Molar mass
0.021 = mass of CO2 /44
Cross multiply
Mass of CO2 = 0.021 × 44
Mass of CO2 = 0.924 g.