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iren [92.7K]
3 years ago
9

Write down the compounds that does not have an alpha hydrogen.

Chemistry
1 answer:
Yuliya22 [10]3 years ago
6 0

Answer:

This question appears incomplete

Explanation:

However, an alpha hydrogen is the hydrogen that is found on the alpha, α-carbon in an organic molecule. Alpha carbon is referred to the first carbon that is attached to a functional group. Generally, compounds that do not have alpha carbon do not have alpha hydrogen. For example, first member of all functional groups do not usually have alpha carbon and hence do not have alpha hydrogen.

Also, Alkanes, alkenes and alkynes do not have also

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I believe it is 9.3x10^7
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Classify each process as an endothermic or exothermic process. drag the appropriate items to their respective bins. helpreset ex
myrzilka [38]
Answers:

1) <span>Breaking Solvent-Solvent Attractions is an Endothermic Process.

2) </span><span>Breaking Solute-Solute Attractions is an Endothermic Process.

3) </span><span>Forming Solute-Solvent Attractions is an Exothermic Process.

Explanation:
                   When a solute is dissolved in solvent it either releases heat or absorbs heat depending upon the the interactions broken and interactions formed. At first, the solvent solvent interactions are broken , this process requires heat which is provided either from external source or is provided by the forming of solute solvent bond forming process which is exothermic.

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7 0
3 years ago
Read 2 more answers
1, 2 and 3 ........
Orlov [11]
2.) Average atomic mass =Σ (abundance x molar mass) /100 = (12.64 x 302.04 + 18.23 x 304.12 + 69.13 x 305.03) /100 =304.486 u(Dalton) . This is avg atomic mass.

8 0
3 years ago
When aqueous solutions of manganese(II) iodide and sodium phosphate are combined, solid manganese(II) phosphate and a solution o
Feliz [49]

Answer:

The net ionic equation for the given reaction :

3Mn^{2+}(aq)+2PO_4^{3-}(aq)\rightarrow Mn_3(PO_4)_2(s)

Explanation:

3MnI_2(aq)+2Na_3PO_4_2(aq)\rightarrow Mn_3(PO_4)_2(s)+6NaI(aq)...[1]

MnI_2(aq)\rightarrow Mn^{2+}(aq)+2I^-(aq)..[2]

Na_3PO_4(aq)\rightarrow 3Na^{+}(aq)+PO_4^{3-}(aq)...[3]

NaI(aq)\rightarrow Na^+(aq)+I^-(aq)

Replacing MnI_2(aq) , NaI and Na_3PO_4(aq) in [1] by usig [2] [3] and [4]

3Mn^{2+}(aq)+6I^-(aq)+6Na^{+}(aq)+2PO_4^{3-}(aq)\rightarrow Mn_3(PO_4)_2(s)+6Na^+(aq)+6I^-(aq)

Removing the common ions present ion both the sides, we get the net ionic equation for the given reaction [1]:

3Mn^{2+}(aq)+2PO_4^{3-}(aq)\rightarrow Mn_3(PO_4)_2(s)

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3 years ago
The amount of dissolved salt in water is know as
Aleksandr [31]

Answer:

The water is solvent and the salt is solute

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3 years ago
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