Explanation:
Atomic size gradually decreases from left to right across the periodic table because within a period of elements, all electrons are added to the same shell. However, at the same time, protons are being added to the nucleus, making it more positively charged. The effect of increasing proton number is greater than that of the increasing electron number. Therefore, there is a stronger nuclear attraction. This means that the nucleus attracts the electrons more strongly, pulling the atom's electron shells closer to the nucleus. As a result, the atomic diameter of the atom decreases.
Answer:
9.62 μm
Explanation:
From the question given above, the following data were obtained:
Frequency (f) = 31.2 THz
Wavelength (λ) =..?
Next, we shall convert 31.2 THz to Hz.
This can be obtained as follow:
Recall:
1 THz = 1×10¹² Hz
Therefore,
31.2 THz = 31.2 THz × 1×10¹² Hz / 1 THz
31.2 THz = 3.12×10¹³ Hz
Therefore, 31.2 THz is equivalent to 3.12×10¹³ Hz.
Finally, we shall determine the wavelength (λ) infrared radiation as follow:
Frequency (f) = 3.12×10¹³ Hz.
Velocity (v) = 3×10⁸ m/s
Wavelength (λ) =..?
V = λf
3×10⁸ = λ × 3.12×10¹³
Divide both side by 3.12×10¹³
λ = 3×10⁸ / 3.12×10¹³
λ = 9.62×10¯⁶ m
Converting 9.62×10¯⁶ m to micro metre (μm) we have:
1 m = 1×10⁶ μm
Therefore,
9.62×10¯⁶ m = 9.62×10¯⁶ m × 1×10⁶ μm / 1 m
9.62×10¯⁶ m = 9.62 μm
Therefore, the wavelength of the infrared radiation is 9.62 μm
Answer: The vapor pressure of water at 298 K is 3.565kPa.
Explanation:
The vapor pressure is determined by Clausius Clapeyron equation:
where,
= initial pressure at 298 K = ?
= final pressure at 373 K = 101.3 kPa
= enthalpy of vaporisation = 41.1 kJ/mol = 41100 J/mol
R = gas constant = 8.314 J/mole.K
= initial temperature = 298 K
= final temperature = 373 K
Now put all the given values in this formula, we get
![\log (\frac{101.3}{P_1})=\frac{41100}{2.303\times 8.314J/mole.K}[\frac{1}{298K}-\frac{1}{373K}]](https://tex.z-dn.net/?f=%5Clog%20%28%5Cfrac%7B101.3%7D%7BP_1%7D%29%3D%5Cfrac%7B41100%7D%7B2.303%5Ctimes%208.314J%2Fmole.K%7D%5B%5Cfrac%7B1%7D%7B298K%7D-%5Cfrac%7B1%7D%7B373K%7D%5D)
Therefore, the vapor pressure of water at 298 K is 3.565kPa.
1 mole = 6.02 * 10^23 atoms
This is known as Avogadro's Number. This value is approximate.
