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tamaranim1 [39]
3 years ago
13

Why is alloy stainless steel used instead of pure iron for the ball of pen of pure iron for a ball of pen

Chemistry
1 answer:
Anna [14]3 years ago
7 0

Answer:

so it want get so hot

Explanation:

so you want get burned

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PLEEASE HELP TIMED WILL GIVE BRAINLIEST TO CORRECT ANSWER NLY PLEASEEEE HELPPPP
Arturiano [62]

Answer:

1) 1.15 mol

2) M=0.45

3) 22.5 mL

4) 6.25 mL

Explanation:

1)

550 mL= 0.55 L

M= mol solute/ L solution

mol solute= M * L solution

mol solute= (2.1 M * 0.55 L )        M=1.15 mol solute

2)

155 mL = 0.155 L

80 g  -> 1 mol NH4NO3

5.61 g -> x

x= (5.61 g * 1 mol NH4NO3)/80 g       x= 0.07 mol NH4NO3

M=(0.07 mol NH4NO3)/0.155 L         M=0.45

3) M1V1=M2V2

V1= M2V2/M1

V1= (0.500 M * 0.225 L)/5.00 M             V1=0.0225 L =22.5 mL

4) M1V1=M2V2

V1= M2V2/M1

V1= (0.25 M * 0.45 L)/ 18.0 M

V1=6.25 x 10^-3 L = 6.25 mL

8 0
3 years ago
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There are 70 fisherman and 5 sea bass in the lake. Are sea bass considered a limiting factor?
Olin [163]

Answer:

yes

Explanation:

8 0
3 years ago
a piece of wood sinks in ethanol but floats in gasoline. what can you determine about the three different densities?
lakkis [162]
Wood sinks in ethanol => wood has higher density than ethanol.
wood floats in gasoline=> wood has lower density than gasoline
4 0
3 years ago
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The image below shows how wolves and dogs compare to some other animals in the levels of classification.
Mariana [72]
Insects and dogs are both in the Animalia classification.
8 0
3 years ago
46.
Ira Lisetskai [31]

Answer : The volume of O_2 gas needed are, 90 L

Explanation : Given,

Volume of H_2S = 60 L

Now we have to determine the volume of O_2 needed.

As we know that at STP, 1 mole of gas contains 22.4 L volume of gas.

The given balanced chemical reaction is:

2H_2S(g)+3O_2(g)\rightarrow 2SO_2(g)+2H_2O(g)

By the stoichiometry we can say that, 2 moles of H_2S react with 3 moles of oxygen gas to give 2 moles of SO_2 gas and 2 moles of water vapor.

From the balanced reaction we conclude that,

As, 2\times 22.4L volume of H_2S react with 3\times 22.4L volume of O_2 gas

So, 60L volume of H_2S react with \frac{3\times 22.4L}{2\times 22.4L}\times 60L=90L volume of O_2 gas

Thus, the volume of O_2 gas needed are, 90 L

3 0
3 years ago
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