Explanation:
Given parameters:
Number of moles of the sulfur trioxide = 1.55kmol = 1.55 x 10³mole
Unknown:
Mass of the sulfur trioxide = ?
Solution:
To solve for the mass of the sample of sulfur trioxide:
- Find the molar mass of the compound i.e SO₃
atomic mass of S = 32g
O = 16g
molar mass = 32 + 3(16) = 80g/mol
mass of SO₃ = number of moles x molar mass
mass of SO₃ = 1.55 x 10³ x 80 = 124000g or 124kg
Learn more:
mole calculation brainly.com/question/13064292
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If a sample of gas is a 0.622-gram, volume of 2.4 L at 287 K and 0.850 atm. Then the molar mass of the gas is 7.18 g/mol
<h3>What is an ideal gas equation?</h3>
The ideal gas law (PV = nRT) relates to the macroscopic properties of ideal gases.
An ideal gas is a gas in which the particles (a) do not attract or repel one another and (b) take up no space (have no volume).
Given :
The ideal gas equation is given below.
n = PV/RT
n = 86126.25 x 0.0024 / 8.314 x 287
n = 0.622 / molar mass (n = Avogardos number)
Molar mass = 7.18 g
Hence, the molar mass of a 0.622-gram sample of gas having a volume of 2.4 L at 287 K and 0.850 atm is 7.18 g
More about the ideal gas equation link is given below.
brainly.com/question/4147359
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Answer: 4.7432 L
Explanation:
Use stoichiometry: .4235 mol CuCl2 (1 mol I2 / 2 mol CuCl2)(22.4 L / 1 mol I2) = 4.7432 L :)
Answer:
Option 4. 14.8 g
Explanation:
3NO2 + H2O → 2HNO3 + NO
First let us calculate the molar mass of NO2 and NO. This is illustrated below;
Molar Mass of NO2 = 14 + (2x16) = 14 + 32 = 46g/mol
Mass of NO2 from the question = 3 x 46 = 138g.
Molar Mass of NO = 14 +16 = 30g/mol
From the equation,
138g of NO2 reacted to produce 30g of NO
Therefore, 68.2g of NO2 will react to produce = (68.2 x 30)/138 = 14.8g of NO.
Answer:
The energy absorbed in the first move is greater than the energy released in the second move
Explanation:
Electrons require (absorb) energy to move to a higher energy level when there is a large external heat source, the presence of an electric field or by colliding with other electrons
And the amount of energy absorbed by the electron is exactly equal to the change in the energy state between the initial energy level of the electron and the destination energy level
Therefore, given that the energy level of the electron at level 2 is higher than the energy level of the electron when at level 1, we have;
The difference in the energy level between level 4 and level 1 is greater than the difference in the energy level between level 4 and level 2 and more energy is absorbed and therefore, released when the electron moves from level 1 to level 4 than when the electron drops from level 4 to level 2.
The most likely result is that 'the energy absorbed in the first move is greater than the energy released in the second move'.
