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solong [7]
3 years ago
15

Solve -2/3x > 8 or -x < 4.

Mathematics
1 answer:
horrorfan [7]3 years ago
8 0

Answer:

<u>x < -12</u>

Step-by-step explanation:

-2/3x > 8

-2/3x * (-3/2) < (-3/2)

cancel the common factor of 2

-x/3*-3<8* (-3/2)

Multiply

x<8 * (-3/2)

Simplify

x < 4 * -3

Multiply

x<-12

-2/3x > 8

= x < -12

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Solve the equation 2x^{2}-12x-14=x^{2}-8x2x 2 −12x−14=x 2 −8x to the nearest tenth
dlinn [17]

Answer:

x = 6.2 or -2.2

Step-by-step explanation:

Given:

2x² - 12x - 14 = x² - 8x

Collect like terms

2x² - x² - 12x + 8x - 14 = 0

x² - 4x - 14 = 0

a = 1

b = -4

c = -14

x = -b ± √b² - 4ac / 2a

= -(-4) ± √(-4)² - 4(1)(-14) / 2(1)

= 4 ± √16 -(-56) / 2

= 4 ± √16 + 56 / 2

= 4 ± √72 / 2

= 4 ± 6√2 /2

= 4/2 + 6√2/2 or 4/2 - 6√2/2

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