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Sindrei [870]
3 years ago
7

9=7+a a+8=b+5 value of b

Mathematics
1 answer:
kvv77 [185]3 years ago
5 0
B is 5, you can solve this by first finding the value of a, which is 2, and then plug it into the other equation. 8+2=10 so we must also make the other side 10. We then do 10-5=5, 5 is the value of b
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givi [52]

The diagnonals of a parallelogram bisect each other ,

so

=》 BD = 3x × 2

=》BD = 6x

and there's given that

=》

BD = \dfrac{3}{5} AC

=》

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=》

x =  \dfrac{24}{6}

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x = 4

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The radius of the large sphere is double the radius of the small sphere. How many times does the volume of the large sphere than
pshichka [43]

Answer:

8 times larger.

Step-by-step explanation:

The radius of the large sphere is double the radius of the small sphere.

Question asked:

How many times does the volume of the large sphere than the small sphere

Solution:

<u>Let radius of the small sphere = </u>x<u />

<u>As the radius of the large sphere is double the radius of the small sphere:</u>

Then, radius of the large sphere = 2x

To find that how many times is the volume of the large sphere than the small sphere, we will <em><u>divide the volume of large sphere by  volume of small sphere:-</u></em>

For smaller sphere: Radius = x

Volume \ of \ sphere = \frac{4}{3} \pi r^{3}

                             =\frac{4}{3} \pi x^{3}

For larger sphere: Radius = 2x

Volume \ of \ sphere = \frac{4}{3} \pi r^{3}

                             =\frac{4}{3} \pi (2x)^{3}

Now, we will divide volume of the larger by the smaller one:

=\frac{4}{3} \pi (2x)^{3}\div\frac{4}{3} \times\frac{\pi }{1 } \times x^{3}\\  \\ =\frac{4}{3} \pi\times8x^{3} \times\frac{3}{4\pi }\  \times\frac{1}{x^{3} }

\frac{4}{3}\pi\   is \ canceled\  by\  \frac{3}{4\pi } \ and\ also\ x^{3} is\ canceled\ by \ \frac{1}{x^{3} }

<u>Now, we have</u>

= \frac{8}{1}

Therefore, the volume of the large sphere is 8 times larger than the smaller sphere.

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Answer:

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