Question

A 17.98-g piece of iron absorbs 2056.5 joules of heat energy, and its temperature changes from 25°C to 200°C. Calculate the specific heat capacity of iron.

Answer 1

Answer: $0.65\ J/g.^{\circ}C$

Explanation:

Given

Mass of iron piece is $m=17.98\ g$

Heat absorbed $Q=2056.5\ J$

Temperature changes from $25^{\circ}C\ to\ 200^{\circ}C$ i.e.

$\Delta T=200-25=175^{\circ}C$

Heat absorbed is given by $Q=mc\Delta T\quad [c=\text{specific heat of material}]$

Insert the values

$\Rightarrow 2056.5=17.98\times c\times 175\\\\\Rightarrow c=\dfrac{2056.5}{3146.5}\\\\\Rightarrow c=0.65\ J/g.^{\circ}C$

Thus, the specific heat of iron is $0.65\ J/g.^{\circ}C$