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mr Goodwill [35]
3 years ago
6

A 17.98-g piece of iron absorbs 2056.5 joules of heat energy, and its temperature changes from 25°C to 200°C. Calculate the spec

ific heat capacity of iron.
Chemistry
1 answer:
V125BC [204]3 years ago
7 0

Answer: 0.65\ J/g.^{\circ}C

Explanation:

Given

Mass of iron piece is m=17.98\ g

Heat absorbed Q=2056.5\ J

Temperature changes from 25^{\circ}C\ to\ 200^{\circ}C i.e.

\Delta T=200-25=175^{\circ}C

Heat absorbed is given by Q=mc\Delta T\quad [c=\text{specific heat of material}]

Insert the values

\Rightarrow 2056.5=17.98\times c\times 175\\\\\Rightarrow c=\dfrac{2056.5}{3146.5}\\\\\Rightarrow c=0.65\ J/g.^{\circ}C

Thus, the specific heat of iron is 0.65\ J/g.^{\circ}C

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