1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
mel-nik [20]
3 years ago
12

If the particles of matter that make up a substance are relatively far apart and can move freely, the substance is in what state

?
gaseous
liquid
solid​
Chemistry
1 answer:
Novay_Z [31]3 years ago
5 0

Answer:

Gaseous

Explanation:

Gasses can move freely and do not form the shape of their containers

Liquids are more free than solids, but they conform to the shape of their container

Solids are not free

You might be interested in
What are the intermolecular forces of Sulfate ion
Salsk061 [2.6K]

Answer:

oh it's easy

Explanation:

Take the hydrate

N

a

2

S

2

O

3

∙

5

H

2

O

. Are there ionic forces between the

N

a

+

and the

S

2

O

2

−

3

and ion-dipole forces between the cation/anions and the water?

3 0
3 years ago
820 g Li2SO4 is dissolved into 2500 mL of solution. What is the molar concentration?
Andreas93 [3]

Molarity is defined as the moles of solute per liter of solution. M=\frac{n}{V}. Where M is molarity, n is the number of moles and V is the volume. First we must find the molar mass of Li_2SO_4 which is 109.98 g/mol

Li_2SO_4= 2 \times Li_{Ar} + S_{Ar} + 4 \times O_{Ar}\\= (2 \times 6.941 + 32.1 + 4 \times 16.0) = 109.98 g/mol

820\ g\ Li_2SO_4 \times \frac{mol}{109.98\ g}= 7.46\ mol\ Li_2SO4

Then we find the molarity using above equation

M= \frac{n}{V} = \frac{7.46 mol}{2500ml} \times\frac{1000ml}{L} = 2.98\ M


6 0
3 years ago
Calculate the mass of NaCO3 used in experiment. SHOW WORK — 15 points!!
Liono4ka [1.6K]

The mass of sodium bicarbonate (NaHCO₃) used in the experiment is 1.997 g

<h3>Calculating mass </h3>

From the question we are to calculate the mass of NaHCO₃ (sodium bicarbonate) used in the experiment

From the given information

Mass of empty evaporating dish = 46.233g

Mass of evaporating dish + Sodium bicarbonate = 48.230g

∴ Mass of sodium bicarbonate (NaHCO₃) = [Mass of evaporating dish + Sodium bicarbonate] - [Mass of empty evaporating dish]

Mass of sodium bicarbonate (NaHCO₃) = 48.230g - 46.233g

Mass of sodium bicarbonate (NaHCO₃) = 1.997 g

Hence, the mass of sodium bicarbonate (NaHCO₃) used in the experiment is 1.997 g

Learn more on Calculating mass here: brainly.com/question/15268826

5 0
2 years ago
If a cold piece of metal is added to hot water, the water will
Roman55 [17]

Answer:

Over time the metal will cool and the water will heat up. Eventually the two objects will have the same temperature

Explanation:

5 0
3 years ago
What ion will ACIDS dissociate into in water
Phoenix [80]

Answer:

Hydron

Chemistry

hydrogen

An Arrhenius acid is therefore any substance that ionizes when it dissolves in water to give the H+, or hydrogen, ion. An Arrhenius base is any substance that gives the OH-, or hydroxide, ion when it dissolves in water.

Explanation:

4 0
3 years ago
Other questions:
  • 1.15 g of a metallic element reacts with 300 cm3 of oxygen at 298 K and 1 atm pressure, to form. an oxide which contains O2– ion
    9·1 answer
  • (r)-3-bromo-2,3-dimethylpentane will undergo a substitution reaction in the presence of methanol when heat is applied. complete
    6·1 answer
  • Is sandy, silt, or clay loam better? and why?
    12·1 answer
  • Asap help <br> It's very important
    10·2 answers
  • Елементите от IА и IIА групи на Периодичната система
    6·1 answer
  • How many moles are in 8.25×10²⁵ molecules of water(H20)?​
    10·1 answer
  • Why must energy be used to produce the colors seen
    8·2 answers
  • Use the bond energies to answer the question.
    6·1 answer
  • when 1.00 mol co and 3.00 mol h2 are placed into a 10.0 l vessel at 9270c and allowed to come to equilibrium, the mixture is fou
    14·1 answer
  • 7. What is the molarity of the nitrate ion that is found in a solution made by dissolving 6.25g
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!