Combine the like terms 2g + 15 + 3g + g + g- 18
1 answer:
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Answer:
<em>Two possible answers below</em>
Step-by-step explanation:
<u>Probability and Sets</u>
We are given two sets: Students that play basketball and students that play baseball.
It's given there are 29 students in certain Algebra 2 class, 10 of which don't play any of the mentioned sports.
This leaves only 29-10=19 players of either baseball, basketball, or both sports. If one student is randomly selected, then the propability that they play basketball or baseball is:
P = 0.66
Note: if we are to calculate the probability to choose one student who plays only one of the sports, then we proceed as follows:
We also know 7 students play basketball and 14 play baseball. Since 14+7 =21, the difference of 21-19=2 students corresponds to those who play both sports.
Thus, there 19-2=17 students who play only one of the sports. The probability is:
P = 0.59
Answer:
5.33
Step-by-step explanation:
move the 4 out of the summation because just a constant multiplier
4 *sum from 1 to 10 for (1/4)^(n-1) [sorry i don't know how to write sums using latex)
The formula for the geometric sum is :
First term*(1-multiplier^n)/(1-multiplier), formally
Here multiplier is 1/4
First term is (1/4)^(1-1) = 1
Thus the value of sum is which equals
We factored out 4 so its which is
This equals 5.333328247 which is 5.33 to the nearest hundredth