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tatuchka [14]
3 years ago
14

PLEASE HELP! WILL MARK BRAINLIEST!

Mathematics
2 answers:
dedylja [7]3 years ago
5 0

Answer:

at first put the value of X

after that do the equation.

Step-by-step explanation:

hope it will help you

maria [59]3 years ago
5 0

Answer:

a = 2

Step-by-step explanation:

substitute x with the number 5.

5+8a=25+5a-7a

subtract 5a from both sides

5+3a=25-7a

add 7a to both sides

5+10a = 25

subtract 5 from both sides

10a=20

divide both sides by 10

a = 2

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Calculate CDEFtrapezium
pantera1 [17]

。☆✼★ ━━━━━━━━━━━━━━  ☾  

You need to find the length of A F and BC first

Lets call BC --> 'x'

Lets form an equation

9 + 9 + x + x = 28

18 + 2x = 28

- 18

2x = 10

/ 2

x = 5

So now we have the length BC

We can subtract this length from the 11cm to find the vertical height of the trapezium

11 - 5 = 6

Now we have all we need to work it out.

area = (a + b) / 2 x h

area = (5 + 9) / 2 x 6

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3 years ago
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Find the general term of {a_n}
Assoli18 [71]

From the given recurrence, it follows that

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and so on down to the first term,

a_{n+1} = 2^na_1 + \displaystyle \sum_{k=0}^{n-1}2^k

(Notice how the exponent on the 2 and the subscript of <em>a</em> in the first term add up to <em>n</em> + 1.)

Denote the remaining sum by <em>S</em> ; then

S = 1 + 2 + 2^2 + \cdots + 2^{n-1}

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S - 2S = 1 - 2^n \implies S = 2^n - 1

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a_{n+1} = 4\cdot2^n + S \\\\ a_{n+1} = 2^2\cdot2^n + 2^n-1 \\\\ a_{n+1} = 2^{n+2} + 2^n - 1 \\\\\implies \boxed{a_n = 2^{n+1} + 2^{n-1} - 1}

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