The percentage of water of crystallization in blue vitriol is 36.07%.
M(H₂O) = 2Ar(H) + Ar(O) x g/mol
M(H₂O) = 2 + 16 x g/mol
M(H₂O) = 18 g/mol; molar mass of water
M(CuSO₄·5H₂O) = Ar(Cu) + Ar(S) + 4Ar(O) + 5Mr(H₂O) x g/mol
M(CuSO₄·5H₂O) = 63.5 + 32 + 64 + 90 x g/mol
M(CuSO₄·5H₂O) = 249.5 g/mol; molar mass of copper sulphate pentahydrate
The percentage of water: 5M(H₂O) / M(CuSO₄·5H₂O) x 100%
The percentage of water: 90 g/mol / 249.5 g/mol x 100%
The percentage of water = 36.07%
More about blue vitriol: brainly.com/question/8895853
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Answer:
<h2>- It could be stretched into a thin wire.</h2>
Explanation:
As per the question, the most rational claim that the student can make about the aluminum metal is that 'it could be stretched into a thin wire' without breaking which shows its ductility. It is one of the most significant characteristics of a metal. Metals can conduct electricity in any state and not only when melted. Thus, option A is wrong. Options C and D are incorrect as metals neither have the same shape always nor do they break on hitting with a hammer. Therefore, <u>option E</u> is the correct answer.
It allows a scientist to understand the history of metamorphic rock by estimating the temperature, depth, and pressure at which a rock undergoes metamorphism.
Hope that helped!
Answer:
The concentration of the copper (II) sulfate solution is 2.06 * 10^2 μmol/L or 2.06 * 10^2 μM
Explanation:
The concentration of a solution is the amount of solute dissolved in a given volume of solution. In this case, the concentration of the copper(II) sulfate solution in micromoles per liter (symbol ) is the number of micromoles of copper(II) sulfate dissolved in each liter of solution. To calculate the micromoles of copper(II) sulfate dissolved in each liter of solution you must divide the total micromoles of solute by the number of liters of solution.
Here's that idea written as a formula: c= n/V
where c stands for concentration, n stands for the total micromoles of copper (II) sulfate and V stands for the total volume of the solution.
You're not given the volume of the solution in liters, but rather in milliliters. You can convert milliliters to liters with a unit ratio: V= 150. mL * 10^-3 L/ 1 mL = 0.150 L
Next, plug in μmol and liters into the formula to divide the total micromoles of solute by the number of liters of solution: c= 31 μmol/0.150 L = 206.66 μmol/L
Convert this number into scientific notation: 2.06 * 10^2 μmol/L or 2.06 * 10^2 μM
