The answer to the question is a.
Answer:
The mean free path = 2.16*10^-6 m
Explanation:
<u>Given:</u>
Pressure of gas P = 100 kPa
Temperature T = 300 K
collision cross section, σ = 2.0*10^-20 m2
Boltzmann constant, k = 1.38*10^-23 J/K
<u>To determine:</u>
The mean free path, λ
<u>Calculation:</u>
The mean free path is related to the collision cross section by the following equation:

where n = number density

Substituting for P, k and T in equation (2) gives:

Next, substituting for n and σ in equation (1) gives:

Answer:
II. The reaction is exothermic.
III. The enthalpy term would be different if the water formed was gaseous.
Explanation:
For the reaction:
C₂H₅OH(l) + 3O₂(g) → 2CO₂(g) + 3H₂O(l)
The ΔH is -1.37×10³ kJ. As the change in enthalpy is <0,<em> II. The reaction is exothermic.</em>
The ΔH formation of a compound is different if the chemical is in liquid or gaseous phase. For that reason: <em>III. The enthalpy term would be different if the water formed was gaseous.</em>
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I hope it helps!
Answer: Isotope Oxygen 18 will remain the same before and after the reaction because the amount of neutrons are the same in a isotope
Explanation:
Isotopes 18-17 and 16 are the most stable in earth. Keep in mind that a Isotope is an atom that has equal amount of protons and electrons but neutrons ( as you can see in the imagine below) . That is why, an isotope like oxygen 18 will remain the same in a chemical reaction, because there is only a electron transfer when doing a new molecule.
Answer:
A
Explanation:
Since water is polar, we need for there to be a polar solute. This eliminates options B and D.
Now to choose between A and C, we can look at the compounds mentioned.
For A, NH3 is mentioned, which is a polar substance.
However, for C, H2 is mentioned, which is a nonpolar molecule, contrary to what is stated by the option.
Therefore, A is the answer.