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Monica [59]
3 years ago
13

How to solve 2 and 3

Chemistry
1 answer:
GarryVolchara [31]3 years ago
3 0
Use the Heat formula for both problems.

q=m*c*∆t

Where
q= heat in Joules
m= mass in grams
c= specific heat which is a constant 4.18
∆t= change in temperature
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When the temperature of the gas changes from cold to hot, the amount of pressure is ___________.
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The pressure would increase. When the temperature change form cold to hot, the gas will find ways to escape from containment. Thus, if it cannot escape that pressure will keep on increasing as the temperature rises.
6 0
3 years ago
A(n) ____ consists of atoms that have a specific number of protons in their nuclei.
Kamila [148]

Answer:

Solution i think

Explanation:

7 0
3 years ago
helium-filled balloon at sea level has a volume of 2.1 L at 0.998 atm and 36°C. If it is released and rises to an elevation at w
elena55 [62]

the new volume of the balloon would be 2.3 L

8 0
4 years ago
For the following reaction, 22.0 grams of nitrogen monoxide are allowed to react with 5.80 grams of hydrogen gas . nitrogen mono
mash [69]

NO is the limiting reagent and 4.34 g is the amount of the excess reagent that remains after the reaction is complete

<h3>What is a limiting reagent?</h3>

The reactant that is entirely used up in a reaction is called as limiting reagent.

The reaction:

2NO(g) +2H_2(g) → N_2 +2H_2O

Moles of nitrogen monoxide

Molecular weight: M_(_N_O_)=30g/mol

n_(_N_O_) =\frac{mass}{molar \;mass}

n_(_N_O_) =\frac{22.0}{30g/mol}

n_(_N_O_) = 0.73 mol

Moles of hydrogen

Molecular weight: M_(_H_2_)=30g/mol

n_(_H_2_) =\frac{mass}{molar \;mass}

n_(_H_2_) =\frac{5.80g}{2g/mol}

n_(_H_2_) = 2.9 mol

Hydrogen gas is in excess.

NO is the limiting reagent.

The amount of the excess reagent remains after the reaction is complete.

n_(_N_2_) = (2.9 mol- 0.73 mol NO x \frac{1 \;mol \;of \;H_2}{2 \;mole \;of \;NO}) x \frac{2g \;of \;H_2}{mole \;of \;H_2}

n_(_N_2_) =4.34 g

Learn more about limiting reagents here:

brainly.com/question/26905271

#SPJ1

5 0
2 years ago
What is the energy change associated with 1.5 mole of D being formed? 
AleksandrR [38]

Answer:

–36 KJ.

Explanation:

The equation for the reaction is given below:

2B + C —› D + E. ΔH = – 24 KJ

From the equation above,

1 mole of D required – 24 KJ of energy.

Now, we shall determine the energy change associated with 1.5 moles of D.

This can be obtained as illustrated below:

From the equation above,

1 mole of D required – 24 KJ of energy

Therefore,

1.5 moles of D will require = 1.5 × – 24 = –36 KJ.

Therefore, –36 KJ of energy is associated with 1.5 moles of D.

3 0
3 years ago
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