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3 years ago

How to solve 2 and 3

Chemistry

1 answer:

GarryVolchara [31]3 years ago

3 0

Use the Heat formula for both problems.

q=m*c*∆t

Where
q= heat in Joules
m= mass in grams
c= specific heat which is a constant 4.18
∆t= change in temperature

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An aqueous solution of ammonium sulfate is allowed to react with an aqueous solution of calcium nitrate.

Salsk061 [2.6K]

<u>Answer:</u> The net ionic equation contains $Ca^{2+}(aq.)$ ions

<u>Explanation:</u>

Net ionic equation of any reaction does not include any spectator ions.

Spectator ions are defined as the ions which does not get involved in a chemical equation. They are found on both the sides of the chemical reaction when it is present in ionic form.

The chemical equation for the reaction of ammonium sulfate and calcium nitrate is given as:

$(NH_4)_2SO_4(aq.)+Ca(NO_3)_2(aq.)\rightarrow CaSO_4(s)2NH_4NO_3(aq.)$

Ionic form of the above equation follows:

$2NH_4^{+}(aq.)+SO_4^{2-}(aq.)+Ca^{2+}(aq.)+2NO_3^{-}(aq.)\rightarrow CaSO_4(s)+2NH_4^+(aq.)+2NO_3^-(aq.)$

As, ammonia and nitrate ions are present on both the sides of the reaction. Thus, it will not be present in the net ionic equation and are spectator ions.

The net ionic equation for the above reaction follows:

$Ca^{2+}(aq.)+SO_4^{2-}(aq.)\rightarrow CaSO_4(s)$

Hence, the net ionic equation contains $Ca^{2+}(aq.)$ ions

5 0

2 years ago

Help me with this please! Do not say "I don't know" to get my points!!!!!!! It is not helpful and disrespectful. THANKS!

MariettaO [177]

no- and na- nano5

na- and na+ nana2

hope this helps

Explanation:

4 0

3 years ago

The air temperature surrounding a snowy driveway is 0ºC. One side of the driveway is shaded, while the other side is sunny. The

ICE Princess25 [194]

Answer:

The snow absorbed radiant energy to produce a physical change.

Explanation:

8 0

3 years ago

Nitrogen makes up what percentage of the atmosphere?

Rudiy27

Nitrogen makes up around 78% of the total atmosphere.

5 0

3 years ago

Read 2 more answers

The equilibrium constant, Kc, is calculated using molar concentrations. For gaseous reactions another form of the equilibrium co

Anarel [89]

Answer:

Kp = 1.41 x 10⁻⁶

Explanation:

We have the chemical equation:

2 A(g) + 3 B(g)⇌ C(g)

In which A and B are the reactants and C is the product. We calculate first the change in the number of moles of gas (Δn or dn):

dn= (sum moles products - sum moles reactants)

= (moles C - (moles A + moles B))

= (1 - (2+3))

= 1 - 5

= -4

We have also the following data:

Kc = 63.2

T= 81∘C + 273 = 354 K

R = 0.082 L.atm/K.mol (it is a constant)

Thus, we introduce the data in the mathematical expression for the relation between Kp and Kc:

$Kc = (RT)^{dn}$ = (0.082 L.atm/K.mol x 354 K)⁻⁴ = 1.41 x 10⁻⁶

3 0

3 years ago