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forsale [732]
3 years ago
7

6. An unknown compound is analyzed and found to consist of 49% carbon, 2.7

Chemistry
1 answer:
Tom [10]3 years ago
4 0

Answer:

Molecular formula = C₆H₄Cl₂

Explanation:

Given data:

Percentage of hydrogen = 2.7%

Percentage of carbon = 49%

Percentage of chlorine = 48.2%

Molar mass of compound = 150 g/mol

Molecular formula = ?

Solution:

Number of gram atoms of H = 2.7 / 1.01 = 2.67

Number of gram atoms of Cl = 48.2 / 16 = 1.36

Number of gram atoms of C = 49 / 12 = 4.08

Atomic ratio:

            C                      :           H             :           Cl

           4.08/ 1.36         :     2.67/1.36       :       1.36/1.36

            3                      :        2                 :        1

C : H : Cl = 3 : 2 : 1

Empirical formula is C₃H₂Cl.

Molecular formula:

Molecular formula = n (empirical formula)

n = molar mass of compound / empirical formula mass

Empirical formula mass = 12×3 + 1.01 ×2 + 35.5 = 73.52 g/mol

n = 150 / 73.52

n = 2

Molecular formula = n (empirical formula)

Molecular formula = 2 (C₃H₂Cl)

Molecular formula = C₆H₄Cl₂

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When answering this question, you must consider the reactivity series. Mg is much higher than Zn in the reactivity series, therefore it can displace the Zn from the solution - displacement reaction.

It seems odd that you'd react Magnesium nitrate with zinc nitrate. Maybe you meant magnesium with zinc nitrate or vice Versa. Because in your case each compound would remain as it is as both Mg and Zn are happy in a relatively stable compound.

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Hope it helps!
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vovangra [49]

Answer:

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