Answer:
C8H12F6
Explanation:
To solve this question we need to find the moles of each atom in order to find the empirical formula (The empirical formula is defined as the simplest whole-number ratio of atoms present in a molecule). Using the empirical formula and the molar mass we can find molecular formula as follows:
<em>Moles C:</em>
2.35g * (1mol / 12g) = 0.1958 moles C
<em>Moles H:</em>
0.294g (1mol /1g) = 0.294 moles H
<em>Moles F -Molar mass: 19.0g/mol-: </em>
Mass F: 5.43g - 2.35g C - 0.294g H = 2.786g F * (1mol / 19.0g) = 0.1466 moles F
The moles of atoms dividing in the moles of F (Lower number of moles) produce the simplest ratio as follows:
C = 0.1958mol C / 0.1466mol F = 1.33
H =0.294mol H / 0.1466mol F = 2
F = 0.1466 mol F / 0.1466mol F = 1
As the empirical formula requires whole numbers, this ratio multiplied 3 times:
C = 4
H = 6
F=3
The empirical formula is:
C4H6F3
With molar mass of:
4C = 12*4 = 48
6H = 1*6 = 6
3F = 19*3 = 57
The molar mass is: 48g/mol + 6g/mol + 57g/mol = 111g/mol
As we know the molecule has a molar mass between 219-225g/mol and the empirical formula is 111g/mol, 2 times empirical formula will produce a molecule with the molar mass of the molecule, that is:
<h3>C8H12F6</h3>
Flourine
Chlorine
Bromine
Iodine
Astatine
Adenine is added to the sequence
Answer:
The volume of the gas decreases also in a 21% based on the Avogadro's law
Explanation:
Based on Avogadro's law, the volume of a gas is directely proportional to the amount of moles of gas when temperature and pressure remain constants.
The formula is:
V1 / n1 = V2 / n2
<em>Where V is volume and n are moles in 1, initial state and 2, final state of the gas.</em>
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At beginning, V1 = 100%, n1 = 100%,
As the chemist removes 21% of the gas, 79% of moles remain = n2.
Replacing:
100% / 100% = V2 / 79%
V2 = 79%, that means:
<h3>The volume of the gas decreases also in a 21% based on the Avogadro's law</h3>
Answer:
No metals. Right side.
Explanation:
On the right. Non metallic elements
