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Delicious77 [7]
2 years ago
13

Element: calcium symbol: Ca Atomic weight: g Mass of one mole: g/mol

Chemistry
1 answer:
Elena-2011 [213]2 years ago
6 0

153g/mols I think this is the answer but not 100% sure.


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Today, the annual rate of tectonic plate movement is observed and measured b
rodikova [14]
Yes I think yesi,m not really suer
4 0
3 years ago
If an object has an acceleration of 9.8 m/s and a force of 58.8N what is the mass of an object ? What could the object be
Makovka662 [10]

Answer:

The mass of an object  is 0.6122 Kg

Explanation:

Given:

Acceleration  = 9.8 m/s

Force  = 58.8 N

To Find:

Mass of an object = ?

Solution:

We know that according to newtons 2nd law

Force is the product of the mass and acceleration

F= ma

where

F = Force

m = mass

a =  Acceleration

Substituting the values,

58.8 = m X  9.8

m= \frac{58.8}{9.8}

m = 0.6122 kg

7 0
2 years ago
22.00 g of CO2 has a volume of 50.00 L and a pressure of 0.8210 atm. What must be the
creativ13 [48]

Answer:

T = 9.875K

Explanation:

The ideal gas Law is PV = nRT.

P = Pressure

V = Volume

n = amount of substance

R =  8.314 J/(K. mol)

T = Temperature in Kelvin

22g CO2

CO2 Molar Mass = 44g/mol

C = 12g/mol

O = 16g/mol

P = 0.8210atm

V = 50L

PV = nRT

0.8210 x 50 = 8.314 x 0.5 x T

41.05 =  4.157T

T = 41.05/4.157

T = 9.875K

3 0
3 years ago
Suppose 200.0 mL of a 2.50 M solution of sodium hydroxide is combined with 400.0 mL of a 1.50 M solution of iron(III) nitrate. W
-BARSIC- [3]

Answer: 83%

Explanation:

The detailed solution is shown in the image attached. First we must work out the balanced reaction equation because accurate solution of the problem must be based on the stoichiometry of the reaction. From the given concentration and volume of reactants, we calculate the amount of substance reacted hence identify the limiting reactant. Lastly we use simple proportion to obtain the theoretical yield of the precipitate. This is now used to calculate the actual yield as shown in the solution attached.

6 0
2 years ago
If 89.6 joules of heat 20.0 grams of iron from 30.0 C to 40.0 C, what is the specific heat of the iron in J/g.C?
atroni [7]

Answer:

 

H = m c ΔT  

89.6 J = (20.0 g) × c × (40.0 - 30.0)°C  

Specific heat of iron, c = 89.6 / [20.0 × (40.0 - 30.0)] J/(g°C) = 0.448 J/(g°C)

4 0
3 years ago
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