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Solnce55 [7]
3 years ago
6

2. force → the rate at which an object changes position; distance divided by time

Chemistry
1 answer:
yaroslaw [1]3 years ago
4 0

Answer:

2. True

3. True

4. False

Explanation:

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If a chemical has a pH of 3, how could you alter its pH value to be more basic?
Andreyy89

Answer; If a chemical has a pH of 3, how could you change its pH value to be more basic? Adding water to a chemical will dilute the acid, thus lowering the pH value to more basic.

6 0
3 years ago
If there is a graduated cylinder containing 20mL of water and a small rock is gently placed inside it, and the water level insid
LekaFEV [45]

Answer:

5

Explanation:

just subtract 20-25 and 5 is left over which is how much the water when up with the rock.

8 0
3 years ago
Read 2 more answers
A cyanide solution with avolume of 12.73 mL was treated with 25.00 mL of Ni2+solution (containing
natima [27]

Answer:

The molarity of this solution is 0,09254M

Explanation:

The concentration of the Ni²⁺ solution is:

Ni²⁺ + EDTA⁴⁻ → Ni(EDTA)²⁻

0,03935L × 0,01307M = 5,143x10⁻⁴ moles Ni²⁺ ÷ 0,03010L =<em>0,01709M Ni²⁺</em>

25,00 mL of this solution contain:

0,01709M × 0,02500L = 4,2716x10⁻⁴ moles of Ni²⁺

The moles of Ni²⁺ that are in excess and react with EDTA⁴⁻ are:

0,01015L × 0,01307M = 1,3266x10⁻⁴ moles of Ni²⁺

Thus, moles of Ni²⁺ that react with CN⁻ are:

4,2716x10⁻⁴ - 1,3266x10⁻⁴ = 2,9450x10⁻⁴ moles of Ni²⁺

For the reaction:

4CN⁻ + Ni²⁺ → Ni(CN)₄²⁻

Four moles of CN⁻ react with 1 mole of Ni²⁺:

2,9450x10⁻⁴ moles of Ni²⁺ × \frac{4 mol CN^-}{1 molNi^{2+}} = <em>1,178x10⁻³ moles of CN⁻</em>

As the volume of cyanide solution is 12,73mL. The molarity of this solution is:

<em>1,178x10⁻³ moles of CN⁻ ÷ 0,01273L = </em><em>0,09254M</em>

I hope it helps!

5 0
3 years ago
PLS I NEED HELP give me examples of an atom
Ugo [173]

Answer:

Neon (Ne)

Hydrogen (H)

Argon (Ar)

Iron (Fe)

Calcium (Ca)

Deuterium, an isotope of hydrogen that has one proton and one neutron.

Plutonium (Pu)

F-, a fluorine anion.

Explanation:

I got u

4 0
3 years ago
Calculate the mass in grams in nine molecules of CH3COOH? Please show how you got your answer.
WINSTONCH [101]
M CH₃COOH: 12u×2 + 1u×4 + 16u×2 =<u> 60u</u>

m 9CH₃COOH: 60u×9 = <u>540u</u>

<em>(1u ≈ 1,66·10⁻²⁴g)</em>
-----------------------------
1u ------- <span>1,66·10⁻²⁴g
540u ---- X
X = 540</span>×<span>1,66·10⁻²⁴g
<u>X = 896,4</u></span><span><u>·10⁻²⁴g


</u>
</span>
7 0
3 years ago
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