The distance from one compression in a sound wave to the next compression is defined as the _________

If i am changing velocity, i must also have _______ and a net _________

Alinara [238K]

if i am changing velocity, i must also have acceleration and a net force

<h2>Newton's first law of motion</h2>

Newton's first law of motion states that if a body is at rest or moving at a constant speed in a straight line, it will remain at rest or keep moving in a straight line at constant speed unless it is acted upon by a force.

According to Newton's first law of motion, without a force acting on an object, its velocity does not change. The net force acts on an object to change its velocity and cause acceleration.

Read more about velocity:

brainly.com/question/4931057

6 0

2 years ago

Planets A and B have the same size, mass, and direction of travel, but planet A is traveling through space at half the speed of

lord [1]

Planet A is heavier than Planet B

Because Planet A is heavier than Planet B, Planet B will be easier to be moved by gravity causing it to move faster than Planet A.

Hope This Helped : )

6 0

3 years ago

At what displacement of a sho is the energy half kinetic and half potential? what fraction of the total energy of a sho is kinet

expeople1 [14]

As we know that KE and PE is same at a given position

so we will have as a function of position given as

$KE = \frac{1}{2}m\omega^2(A^2 - x^2)$

also the PE is given as function of position as

$PE = \frac{1}{2}m\omega^2x^2$

now it is given that

KE = PE

now we will have

$\frac{1}{2}m\omega^2(A^2 - x^2) = \frac{1}{2}m\omega^2x^2$

$A^2 - x^2 = x^2$

$2x^2 = A^2$

$x = \frac{A}{\sqrt2}$

so the position is 0.707 times of amplitude when KE and PE will be same

Part b)

KE of SHO at x = A/3

we can use the formula

$KE = \frac{1}{2}m\omega^2(A^2 - x^2)$

now to find the fraction of kinetic energy

$f = \frac{KE}{TE} = \frac{A^2 - x^2}{A^2}$

$f = \frac{A^2 - (\frac{A}{3})^2}{A^2}$

$f_k = \frac{8}{9}$

now since total energy is sum of KE and PE

so fraction of PE at the same position will be

$f_{PE} = 1 - f_k$

$f_{PE} = 1 - (8/9) = 1/9$

7 0

3 years ago

An airplane is being pushed West by its engines with a force of 350 N as it starts to take off the runway at the Atlanta airport

Marizza181 [45]

Answer:

option C

Explanation:

given,

Force by the engine on plane in West direction = 350 N

Frictional force on the runway = 100 N in east

force exerted by the wind = 100 N in east

net force and direction = ?

consider west to be positive and east be negative.

when airplane will be moving there will be frictional as well as wind resistance will be acting in opposite direction of airplane

Net force = 350 N - 100 N - 100 N

= 150 N

as our answer comes out to be positive so the airplane will be moving in West

hence, the correct answer is option C

8 0

3 years ago

The power lines are at a high potential relative to the ground, so there is an electric field between the power lines and the gr

Amanda [17]

Answer:

The tube should be held vertically and perpendicular to the ground.

Explanation:

Answer: The tube should be held vertically and perpendicular to the ground. The reason is as follows:

Reasoning:

The power lines are parallel to the ground hence, their electric field will be perpendicular to the ground and equipotential surface will be cylindrical.

Hence, if you will put fluorescent tube parallel to the ground then both the ends of the tube will lie on the same equipotential surface and the potential difference will be zero.

So, to maximize the potential the ends of the tube must be on different equipotential surfaces. The surface which is near to the power line has high potential value and the surface which is farther from the line has lower potential value.

hence, to maximize the potential difference, the tube must be placed perpendicular to the ground.

6 0

3 years ago

The distance from one compression in a sound wave to the next compression is defined as the __________.