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3 years ago

100 points and brainliest!!!!

Mathematics

2 answers:

laila [671]3 years ago

7 0

The answer would be letter B

The slope would be 3 and the y- intercept would be -2

Sergeu [11.5K]3 years ago

7 0

Your answer is (B) y= 3x - 2 because The slope would be 3 and the y-intercept would be -2
*~"AB84"~*

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Which of the following equations represents a graph that decreases?

almond37 [142]

D because it is a decimal (lower than 0)

7 0

3 years ago

Use the distributive property to fill in the blanks below.

elena-14-01-66 [18.8K]

Answer:

(5×7)-(5×6) = 5×(7-6)

5 0

3 years ago

The system of equations may have a unique solution, an infinite number of solutions, or no solution. Use matrices to find the ge

Leno4ka [110]

Answer:

Infinite number of solutions.

Step-by-step explanation:

We are given system of equations

$5x+4y+5z=-1$

$x+y+2z=1$

$2x+y-z=-3$

Firs we find determinant of system of equations

Let a matrix A= $\left[\begin{array}{ccc}5&4&5\\1&1&2\\2&1&-1\end{array}\right]$ and B= $\left[\begin{array}{ccc}-1\\1\\-3\end{array}\right]$

$\mid A\mid=\begin{vmatrix}5&4&5\\1&1&2\\2&1&-1\end{vmatrix}$

$\mid A\mid=5(-1-2)-4(-1-4)+5(1-2)=-15+20-5=0$

Determinant of given system of equation is zero therefore, the general solution of system of equation is many solution or no solution.

We are finding rank of matrix

Apply $R_1\rightarrow R_1-4R_2$ and $R_3\rightarrow R_3-2R_2$

$\left[\begin{array}{ccc}1&0&1\\1&1&2\\0&-1&-3\end{array}\right]$ : $\left[\begin{array}{ccc}-5\\1\\-5\end{array}\right]$

Apply $R_2\rightarrow R_2-R_1$

$\left[\begin{array}{ccc}1&0&1\\0&1&1\\0&-1&-3\end{array}\right]$ : $\left[\begin{array}{ccc}-5\\6\\-5\end{array}\right]$

Apply $R_3\rightarrow R_3+R_2$

$\left[\begin{array}{ccc}1&0&1\\0&1&1\\0&0&-2\end{array}\right]$ : $\left[\begin{array}{ccc}-5\\6\\1\end{array}\right]$

Apply $R_3\rightarrow- \frac{1}{2}$ and $R_2\rightarrow R_2-R_3$

$\left[\begin{array}{ccc}1&0&1\\0&1&0\\0&0&1\end{array}\right]$ : $\left[\begin{array}{ccc}-5\\\frac{13}{2}\\-\frac{1}{2}\end{array}\right]$

Apply $R_1\rightarrow R_1-R_3$

$\left[\begin{array}{ccc}1&0&0\\0&1&0\\0&0&1\end{array}\right]$ : $\left[\begin{array}{ccc}-\frac{9}{2}\\\frac{13}{2}\\-\frac{1}{2}\end{array}\right]$

Rank of matrix A and B are equal.Therefore, matrix A has infinite number of solutions.

Therefore, rank of matrix is equal to rank of B.

4 0

3 years ago

How do you solve an inequality that has a fraction (with a variable as the nemurator/demoninator

vichka [17]

Answer:

Solving with an equality is just simply the same as solving any algebra equations. If you were given a fraction, then just multiply both sides.

Example:

4 + $\frac{x}{2}$ > 14

Subtract 4 on both sides:

4 - 4 + $\frac{x}{2}$ > 14 - 4

$\frac{x}{2}$ > 10

Now <em>multiply both sides by 2</em>:

$\frac{x}{2}$ × 2 > 10 × 2

x > 20

3 0

3 years ago

An isosceles trapezoid has base angles of 45° and bases of lengths 8 and 14. The area of the trapezoid is

Mice21 [21]

Answer:

Option A is correct.

Step-by-step explanation:

Given an isosceles trapezoid has base angles of 45° and bases of lengths 8 and 14. we have to find the area of isosceles trapezoid.

An isosceles trapezoid has base angles of 45° and bases of lengths 8 and 14.

From the figure attached , we can see an isosceles trapezoid ABCD,

AB = 8cm and CD=14cm

So we have to find the value of AE which is the height of Trapezoid in order to find area.

In ΔAED

$tan\angle 45 =\frac{AE}{ED}$

⇒ $AE=1\times 3$

∴ AE = DE =3cm

$\text{The area of the trapezoid=}\frac{h}{2}\times (a+b)$

h=3cm, a=14cm, b=8cm

$Area=\frac{3}{2}\times(14+8)=\frac{3}{2}\times 22=33 units^2$

hence, $\text{The area of the trapezoid is }33 units^2$

Option A is correct.

3 0

3 years ago

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