Answer: When using 645 L /s of O2 in a temperature and pressure of 195°C, 0.88 atm respectively, we will get 0.355Kg /s NO
Explanation:
- First we review the equation that represents the oxidation process of the NH3 to NO.
4NH3(g) + 5O2(g) ⟶4 NO(g) +6 H2O(l)
- Second we gather the information what we are going to use in our calculations.
O2 Volume Rate = 645 L /s
Pressure = 0.88 atm
Temperature = 195°C + 273 = 468K
NO molecular weight = 30.01 g/mol
- Third, in order to calculate the amount of NO moles produced by 645L/ s of O2, we must find out, how many moles (n) are 645L O2 by using the general gas equation PV =n RT
Let´s keep in mind that using this equation our constant R is 0.08205Lxatm/Kxmol
PV =n RT
n= PV / RT
n= [ 0.88atm x 645L/s] / [ (0.08205 Lxatm/Kxmol) x 468K]
n= 14.781 moles /s of O2
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Fourth, now by knowing the amount of moles of O2, we can use the equation to calculate how many moles of NO will be produced and then with the molecular weight, we will finally know the total mass per second .
14.781 moles /s of O2 x 4moles NO / 5 moles O2 x 30.01g NO / 1 mol NO x 1Kg NO /1000g NO = 0.355Kg /s NO
Answer:
pressure altitude and radiation
Explanation:
beacuse in atmosphere there is aire pressure atmospheric pressure and ofcourse radiation is there as well as altitude at heights
Answer:
The answer should be B. G-T-A-G-C-T
A pairs with T and G pairs with C.
Answer: Option (D) is the correct answer.
Explanation:
In fusion reaction, two small nuclei combine together to result in the formation of a large nuclei.
Whereas in fission reaction, large nuclei dissociates into two or more small nuclei.
Nuclear fusion releases more energy as compared to nuclear fission.
For example, two hydrogen nuceli fuse together and result in the formation of helium atom along with release of energy.
Answer:
847 mL
Explanation:
Step 1: Find conversion
1 L = 1000 mL
Step 2: Use Dimensional Analysis
<em>We see that Liters and Liters cancel out, so we simply multiply.</em>
847 mL
