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ozzi
3 years ago
15

Which is an example of the practical pursuit of alchemy

Chemistry
1 answer:
morpeh [17]3 years ago
4 0

Answer:

A practical pursuit of alchemy was the development of metallurgy practices.

Explanation:

As alchemists always tried to turn various metals into other things, metalworking techniques were developed even though their experiments were often unsuccessful.

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Which natural polymers are involved with making clothing?
fredd [130]

Answer:

A. wool, silkworm, cocoon, and cellulose

Explanation:

I hope this helped!

7 0
3 years ago
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What is an inference in science
kirza4 [7]
<span>An Inference Is An Idea Or Conclusion Thats Drawn From Evidence And Reasoning. An Inference Is Also An Educated Guess.</span>
4 0
3 years ago
An excited ozone molecule, O3*, in the atmosphere can undergo one of the following reactions,O3* → O3 (1) fluorescenceO3* → O +
Maurinko [17]

Answer:

The simplified expression for the fraction  is  \text {X} =    \dfrac{  {k_3  \times cM} }{k_1 +k_2 + k_3 }

Explanation:

From the given information:

O3* → O3                   (1)    fluorescence

O + O2                      (2)    decomposition

O3* + M → O3 + M    (3)     deactivation

The rate of fluorescence = rate of constant (k₁) × Concentration of reactant (cO)

The rate of decomposition is = k₂ × cO

The rate of deactivation = k₃ × cO × cM

where cM is the concentration of the inert molecule

The fraction (X) of ozone molecules undergoing deactivation in terms of the rate constants can be expressed by using the formula:

\text {X} =    \dfrac{ \text {rate of deactivation} }{ \text {(rate of fluorescence) +(rate of decomposition) + (rate of deactivation) }  } }

\text {X} =    \dfrac{  {k_3 \times cO \times cM} }{  {(k_1 \times cO) +(k_2 \times cO) + (k_3 \times cO \times cM) }  }

\text {X} =    \dfrac{  {k_3 \times cO \times cM} }{cO (k_1 +k_2 + k_3  \times cM) }

\text {X} =    \dfrac{  {k_3  \times cM} }{k_1 +k_2 + k_3  }    since  cM is the concentration of the inert molecule

7 0
4 years ago
If an acid has a ka=1.6x10^-10, what is the acidity of the solution?
LUCKY_DIMON [66]
The information given in the question is not enough to determine the acidity of the solution. This is because, acidity can only be found with the equation: pH = -log [H+].
 In order to determine the acidity of the solution, the half titration point value is needed, this will make it possible to determine the value of H30+.  If the half point titration value is known, then Ka will be equivalent to pH and the value will be evaluated using the equation: - log (1.6 * 10^-10).
5 0
3 years ago
Aspirin was formed to reduce the irritation of salicylic acid. However, aspirin can still disturb the stomach. Which functional
nataly862011 [7]

Answer:

Carboxylic acid

Explanation:

Asprin is a drug that contains the carboxylic acid functional group (R-COOH), ester functional group (R-O-CO-R') and the aromatic group (benzene ring).

When we take in aspirin, it becomes salicylic acid. This metabolite irreversibly inhibits the enzyme cyclooxygenase. Hence the the production of protective prostaglandins is blocked causing inflammation and pain.

6 0
3 years ago
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