Hello,
x^3-12x²-2x+24=x²(x-12)-2(x-12)=(x-12)(x²-2)
=(x-12)(x-√2)(x+√2)
Answer: Second option
Step-by-step explanation:
You need to make the multiplication of the function and the function . Then:
You need to apply the Distributive property:
Therefore, the domain will be all the number that make the denominator equal to zero.
Then, make the denominator equal to zero and solve for x:
Therefore, the domain is: All real values of x except
Answer:
f(x)= (x+8)^2 + 200
Step-by-step explanation:
-b/2a gives you the x coordinate of the vertex and then plug it in for x to get the y coordinate. Put it in the formula (f()x= (x-h)^2 +k).
H is the x coordinate and K is the y coordinate
Answer:
See explanation
Step-by-step explanation:
Triangles ΔABC and ΔBAD are congruent. So,
- AB ≅ BA;
- AC ≅ BD;
- BC ≅ AD;
- ∠ABC ≅ ∠BAD;
- ∠BCA ≅ ∠ADB;
- ∠CAB ≅ ∠DBA.
Consider triangles AEC and BED. In these triangles,
- AC ≅ BD;
- ∠EAC ≅ ∠EBD (because ∠CBA ≅ ∠BAD);
- ∠AEC ≅ ∠BED (as vertical angles).
So, ΔAEC ≅ ΔBED. Thus,
AE ≅ EB.
This means that segment CD bisects segment AD.
Answer:
f(x)=-2x+9 g(x)=-4x^2+5x-3Now, f o g (x) = f{g(x)} = f(4x^2+5x-3) = 2(4x^2+5x-3) + 9 = 8x^2+10x-6 + 9
Step-by-step explanation: