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Brrunno [24]
3 years ago
11

1. Carbon is important because:

Chemistry
2 answers:
TEA [102]3 years ago
7 0

the answer is b. :)))))))))))))

nikklg [1K]3 years ago
3 0

Answer:

B

Explanation:

All organic material has carbon.

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Phoenix [80]
The Answer is 952 cells!

I hope this helps! ^^
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4 years ago
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If the density of blood is 1. 060 g/ml. What is the mass of 6. 56 pints of blood?
ryzh [129]

Answer:

3290 gm

Explanation:

6.56 pints  * 473.1765 ml/pint  * 1.060 g/ml = 3290  gm  

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2 years ago
Why is DDT a dangerous environmental pollutant?
Slav-nsk [51]

it is because it reacts readily with other compounds


4 0
3 years ago
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Calculate the Empirical Formula for the following compound:<br> 0.300 mol of S and 0.900 mole of O.
ziro4ka [17]

Answer:

\boxed {\boxed {\sf SO_3}}

Explanation:

An empirical formula shows the smallest whole-number ratio of the atoms in a compound.

So, we must calculate this ratio. Since we are given the amounts of the elements in moles, we can do this in just 2 steps.

<h3>1. Divide </h3>

The first step is division. We divide the amount of moles for both elements by the <u>smallest amount of moles</u>.

There are 0.300 moles of sulfur and 0.900 moles of oxygen. 0.300 is smaller, so we divide both amounts by 0.300

  • Sulfur: 0.300/0.300= 1
  • Oxygen: 0.900/0.300= 3

<h3>2. Write Empirical Formula</h3>

The next step is writing the formula. We use the numbers we just found as the subscripts. These numbers go after the element's symbol in the formula. Remember sulfur is S and there is 1 mole and oxygen is O and there are 3 moles.

  • S₁O₃

This formula is technically correct, but we typically remove subscripts of 1 because no subscript implies 1 representative unit.

  • SO₃

\bold {The \  empirical \ formula \ for \ the \  compound \ is  \ SO_3}}

6 0
3 years ago
D. Write the name of the branched alkane next to the drawing of the molecule. (2 points)
lbvjy [14]

Answer: hello your question lacks some data attached below is the missing data

answer :

a) 3-methyl heptane

b) 2-methyl pentane

c) 2-methyl heptane

d) 2-methyl hexane

e) 3-methyl hexane

Explanation:

we will select the longest carbon chain as the branched alkane and name it

a) 3-methyl heptane ( first diagram )

b) 2-methyl pentane ( second diagram )

c) 2-methyl heptane ( third diagram )

d) 2-methyl hexane ( fourth diagram )

e) 3-methyl hexane ( fifth diagram )

<em>Note : sixth diagram = first diagram </em>

7 0
3 years ago
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