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Sloan [31]
3 years ago
8

The vitamin ______ is one of the components of coenzyme a, which is involved in _____. pantothenic acid; carboxylation pantothen

ic acid; acyl transfer cobalamin; acyl transfer riboflavin; carboxylation
Chemistry
1 answer:
timama [110]3 years ago
8 0
From what I can recall, I believe the answer is pantothenic acid; acyl transfer. I'm a bio major, hope I helped. :)
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Explain the value of observations during an investigation and suggest one way that you can ensure good observations when you do
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<span>Observation is an important part of investigation.Small evidence may become the key factor for success. Observation is the active acquisition of information from a primary source. In living beings, observation employs the senses. In science, observation can also involve the recording of data via the use of instruments. The term may also refer to any data collected during the scientific activity.</span>
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true or false? 2.0 moles of iron (Fe) would have the same number of atoms as 2.0 moles ph hydrogen (H).
Veronika [31]

Answer:

Explanation:

false

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Which of the following particles of matter could be stopped by a thin piece of aluminum foil?
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Beta particles can be stopped by a thin sheet of aluminum foil.
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3 years ago
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How many grams of glucose, C6H12O6, in 2.47 mole?
statuscvo [17]
First, we need to find the atomic mass of C_{6}H_{12}O_{6}.

According to the periodic table:
The atomic mass of Carbon = C = 12.01
The atomic mass of Hydrogen = H = 1.008
The atomic mass of Oxygen = O = 16

As there are 6 Carbons, 12 Hydrogens and 6 Oxygens, therefore:
The molar mass of  C_{6}H_{12}O_{6} = 6 * 12.01 + 12 * 1.008 + 6 * 16

The molar mass of  C_{6}H_{12}O_{6} = 180.156 grams/mole

Now that we have the molar mass of  C_{6}H_{12}O_{6}, we can find the grams of glucose by using:

mass(of glucose in grams) = moles(of glucose given in moles) * molar mass(in grams/mole)

Therefore,
mass(of glucose in grams) = 2.47 * 180.156
mass(of glucose in grams = 444.99 grams

Ans: Mass of glucose in grams in 2.47 moles = 444.99 grams

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A 1. 00 ml sample of an unknown gas effuses in 11. 1 min. an equal volume of h2 in the same apparatus under the same conditions
Damm [24]

A 1. 00 ml sample of an unknown gas effuses in 11. 1 min. an equal volume of h2 in the same apparatus under the same conditions effuses in 2. 42 minutes then the molar mass of the unknown gas is 41.9.

Molar mass of H2 = 2

Molar mass of unknown gas = ?

rate 1 = 11.1

rate 2 = 2.42

<h3>What is graham law? </h3>

Graham's law states that the rate of diffusion or effusion of a given gas is inversely proportional to the square root of its molar mass.

By apply graham law

Rate1/rate2 = sqrt(MW2/MW1)

[\frac{rate1}{rate2} ]^{2} = \frac{MW2}{2} \\\\\\mw= 2[\frac{11.1}{2.42} ]^{2} \\\\= 20.97 X 2 \\\\= 41.9

Thus, we found that the molar mass of the unknown gas is 41.9.

Learn more about graham's law: brainly.com/question/12415336

#SPJ4

4 0
2 years ago
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