Answer: The pH at the equivalence point for the titration will be 0.65.
Solution:
Let the concentration of be x
Initial concentration of , c = 0.230 M
at eq'm c-x x x
Expression of :
Since ,methyl-amine is a weak base,c>>x so .
Solving for x, we get:
Given, HCl with 0.230 M , it dissociates fully in water which means = 0.230 M
will result in neutral solution, since
Remaining after neutralizing ions
The pH at the equivalence point for the titration will be 0.65.
The answer would be C. CH3COOH, deprotonated
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Answer:
2
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