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seropon [69]
3 years ago
6

How many grams of H3PO4 are produced when 10.0 moles of water react with an excess of P4O10?

Chemistry
1 answer:
sleet_krkn [62]3 years ago
5 0

Answer:

652.6 g of H₃PO₄ are formed

Explanation:

Reaction is:

P₄O₁₀(s) + 6H₂O(l) → 4H₃PO₄(aq)

As P₄O₁₀ is the reactant in excess, the limiting is water.

Ratio is 6:4. We make a rule of three:

6 moles of water produce 4 moles of phosphoric acid

Therefore, 10 moles of water may prodyce (10 .4) / 6 = 6.66 moles of H₃PO₄

We convert the moles to mass:

6.66 moles . 97.9 g / 1mol = 652.6 g

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A gas at constant volume has a pressure of 3.20 atm at 300. K. What will be the pressure of the gas at 290. K?
melomori [17]
  • From the general law of gases: PV = nRT,

where P is the pressure (atm),

V is the volume (L),

n is the number of moles,

R is the general gas constant (8.314 L.atm/mol.K),

T is the temperature in Kelvin

  • at constant volume of the gas: P1T2 = P2T1

P1 = 3.20 atm, T1 = 300 K, T2 = 290 K, P2 = ??

(3.20 atm)(290 K) = P2(300 K)

P2 = (3.20 atm)(290 K)/ (300 K) = 3.093 atm

3 0
3 years ago
Porque el agua reduce la temperatura alta?
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Porque la temperatura de la agua es neutral
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3 years ago
Sodium fluoroacetate (NaO₂C₂H₂F) is a common poison used in New Zealand to control invasive species, such as rats. It can be pre
NISA [10]

Answer:

-219

Explanation:

1.5(339) - 1.5(485) = -219

7 0
3 years ago
The volume of a gas at STP is 7.30 L. What is the quantity of gas in this sample?
sladkih [1.3K]

0.326 moles of gas

Explanation:

Knowing the volume of a gas at standard temperature and pressure (STP) we may calculate the number of moles of the gas using the following formula:

number of moles = volume / 22.4 (L /mole)

number of moles of gas = 7.3 (L) / 22.4 (L /mole)

number of moles of gas = 0.326 moles

Learn more about:

molar volume

brainly.com/question/7144003

brainly.com/question/11160940

#learnwithBrainly

3 0
3 years ago
On the following chemical equation, label the acid, the base, the
beks73 [17]

Answer:

HX (aq)    +     H₂O (l)  ⇄      H₃O⁺ (aq)    +     X⁻ (aq)  

Acid                  Base          Conj. acid          Conj. base  

Explanation:

The equation is:

HX (aq) + H₂O (l)  ⇄   H₃O⁺ (aq) + X⁻ (aq)

This is the typical equilibrium for a weak acid. It would complete if we notice the Ka.

HX (aq) + H₂O (l)  ⇄   H₃O⁺ (aq) + X⁻ (aq)    Ka

1 mol of hypothetic HX acid react to 1 mol of water in order to release a proton and make hydronium and generate the X⁻ anion.

HX will be the acid, in this case a weak one and water will be the base. Water is able to accept a proton to make itslef hydronium

Hydronium is the conjugate acid.

The X⁻ will be the conjugate strong base.

This ion can generate the acid form again, that's why it is strong, because it can make hydrolisis.

X⁻ (aq)  +  H₂O (l)  ⇄  HX (aq) +  OH⁻(aq)     Kb

In this case, the anion will be the conjugate base which it takes a proton from water (acid form) to make a conjugate acid, the HX and a conjugate base, OH⁻

3 0
3 years ago
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