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salantis [7]
3 years ago
14

Find the horizontal range of a projectile launched at 15 degrees to the horizontal with speed of 40m/s​

Chemistry
1 answer:
vfiekz [6]3 years ago
4 0

To Find :

The horizontal range of a projectile launched at 15 degrees to the horizontal with speed of 40 m/s​.

Solution :

The horizontal range of a projectile is given by :

R = \dfrac{u^2 sin 2\theta}{g} ( Here, g is acceleration due to gravity = 10 m/s² )

Putting all value in above equation :

R = \dfrac{40^2 \times sin (2 \times 15)}{10} \ m\\\\R = \dfrac{1600 \times 1}{2\times 10} \ m\\\\R = 80 \ m

Therefore, the horizontal range of projectile is 80 m.

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1. Find the molar mass of the compounds<br>a. K2Cro4​
Luda [366]

Answer:

194.1903

Explanation:

that is for one mole of K2Cro4

8 0
3 years ago
In aqueous solution, hypobromite ion, BrO-, reacts to produce bromate ion, BrO3 -, and bromide ion, Br-, according to the follow
maw [93]

Answer:

22.73s

Explanation:

The reaction is a second order reaction, we know this by observing the unit of the slope.

rate constant = k = 0.056 M-1s-1

the initial concentration of BrO- [A]o = 0.80 M

time = ?

Final concentration [A]t= one-half of 0.80 M = 0.40M

1 / [A]t = kt + 1 / [A]o

1 / 0.40 = 0.056 * t + 1 / 0.80

t = (2.5 - 1.25) / 0.056

t = 22.73s

5 0
3 years ago
The decomposition of acetaldehyde is a second order reaction with a rate constant of 4.71 10−8 L/mol/s. What is the instantaneou
pochemuha

Answer: Rate of decomposition of acetaldehyde in a solution is 1.45\times 10^{-14}mol/Ls

Explanation:

Rate law says that rate of a reaction is directly proportional to the concentration of the reactants each raised to a stoichiometric coefficient determined experimentally called as order.

For a reaction : A\rightarrow products

Rate=k[A]^x

k= rate constant

x = order of the reaction = 2

Rate=4.71\times 10^{-8}L/mol/s\times {5.55\times 10^{-4}M}^2

Rate=1.45\times 10^{-14}

Thus rate of decomposition of acetaldehyde in a solution is 1.45\times 10^{-14}mol/Ls

6 0
2 years ago
1. Based on the observed performance of the air bag models and the amounts of sodium bicarbonate and acetic acid (vinegar) neede
Ira Lisetskai [31]

Sodium bicarbonate and acetic acid are not good substitute for sodium azide in airbags since the require more mass and produce less gas.

<h3>Which is the better chemical for an airbag?</h3>

The chemical equation for the production of nitrogen gas from sodium azide is given below:

  • NaN₃ → 2 Na + 3 N₂

1 mole or 66 go of sodium azide produces 3 moles or 67.2 L of nitrogen gas.

The equation for the production of carbon dioxide from sodium bicarbonate and acetic acid is given below:

  • Na₂CO₃ + CH₃COOH → CH₃COONa + CO₂ + H₂O

1 mole, 106 g of Na₂CO₃ and 1 mole, 82 g of CH₃COOH are required to produce 1 mole or 22.4 L of CO₂.

The mass of sodium azide required is less than that of sodium bicarbonate and acetic acid required. Also, sodium azide produces a greater volume of gas. Therefore, sodium bicarbonate and acetic acid are not good substitute for sodium azide in airbags.

In conclusion, sodium azide is a better choice in airbags.

Learn more about airbags at: brainly.com/question/14954949

#SPJ1

7 0
1 year ago
How many atoms of He are in 5.69 grams?
vfiekz [6]

Answer:

ejdkcndnxk

Explanation:

cnc dkxkcndndmskckf

6 0
3 years ago
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