6a - (b - (3a - (2b + c + 4a - (a + 2b - c))))
6a - (b - (3a - (2b + c + 4a - a - 2b + c)))
6a - (b - (3a - (2b - 2b + 4a - a + c + c)))
6a - (b - (3a - (3a + 2c)))
6a - (b - (3a - 3a - 3c))
6a - (b - 3a + 3a + 3c)
6a - (b + 3c)
6a - b - 3c
x³ + x² - 25x - 25
x²(x) + x²(1) - 25(x) - 25(1)
x²(x + 1) - 25(x + 1)
(x² - 25)(x + 1)
(x² - 5x + 5x - 25)(x + 1)
(x(x) - x(5) + 5(x) - 5(5))(x + 1)
(x(x - 5) + 5(x - 5))(x + 1)
(x + 5)(x - 5)(x + 1)
36x² + 60x + 25
36x² + 30x + 30x + 25
6x(6x) + 6x(5) + 5(6x) + 5(5)
6x(6x + 5) + 5(6x + 5)
(6x + 5)(6x + 5)
(6x + 5)²
Answer:
0.2 or 20%
Step-by-step explanation:
If the times of arrival vary uniformly, there is an equal chance of an employee reporting at any given time between 8:40 and 9:30.
The range between 8:40 and 9:30 is 50 minutes.
The range between 9:00 and 9:10 is 10 minutes.
Therefore, the probability that a randomly chosen employee reports to work between 9:00 and 9:10 is:

The probability is 0.2 or 20%.
Answer:
ten thousands place
Step-by-step explanation:
6 tens of thousands = 60,000
5 thousands= 5,000
3 hundreds= 300
60,000
+ 5,000
<u>+ 300</u>
<u>6</u>5,300