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mestny [16]
3 years ago
13

A cheetah is walking at 1.0 m/s when it sees a zebra 25 m away. what acceleration would be required to reach 20.0 m/s in that di

stance?

Physics
1 answer:
inna [77]3 years ago
8 0
Let
 a = acceleration.
 v = Speed
 r = position
 t = time.
 To find the answer, you must write the equations of speed, and position known and clear the variables that are needed to find the acceleration.
 The answer is a = 7.98m / s ^ 2.
 I attach the solution.

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