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3 years ago

A middle school took all of its 6th grade students on a field trip to see a symphony at

Mathematics

2 answers:

goldenfox [79]3 years ago

4 0

16 % of the theater.

KonstantinChe [14]3 years ago

3 0

Answer:

16%

Step-by-step explanation:

320/2000=.16 or 16%

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How many acres of land are in a rectanglar parcel 234' * 878'

uysha [10]

An acre is 43,560 ft² because the customary system hates you.

Let's find out how many square feet the parcel is so we can convert it into acres.

The area of a rectangle is its base times its height.

A = bh
A = 234 ft * 878 ft
A = 205,452 ft²

Divide by 43,560.

A ≈ <span>4.7165 acres. (round as needed)</span>

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3 years ago

The rectangular prism is to be sliced perpendicular to the shaded face and is to pass through point B, parallel to the front fac

Natasha_Volkova [10]

Answer:

the answer is c i took the quiz

Step-by-step explanation:

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3 years ago

When the rate of change varies from point to point, the relationship is a

marshall27 [118]

Answer: It is a proportional relationship because a proportional relationship is known as a relationship between two quantities, in which the ratio of one quantity to the other quantity is constant.

Step-by-step explanation:

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3 years ago

Read 2 more answers

Expand using the properties and rules for logarithms

malfutka [58]

Consider expression $\log_{\frac{1}{2}}\left(\dfrac{3x^2}{2}\right).$

1. Use property

$\log_a\dfrac{b}{c}=\log_ab-\log_ac.$

Then

$\log_{\frac{1}{2}}\left(\dfrac{3x^2}{2}\right)=\log_{\frac{1}{2}}3x^2-\log_{\frac{1}{2}}2.$

2. Use property

$\log_abc=\log_ab+\log_ac.$

Then

$\log_{\frac{1}{2}}\left(\dfrac{3x^2}{2}\right)=\log_{\frac{1}{2}}3x^2-\log_{\frac{1}{2}}2=\log_{\frac{1}{2}}3+\log_{\frac{1}{2}}x^2-\log_{\frac{1}{2}}2.$

3. Use property

$\log_ab^k=k\log_ab.$

Then

$\log_{\frac{1}{2}}\left(\dfrac{3x^2}{2}\right)=\log_{\frac{1}{2}}3+\log_{\frac{1}{2}}x^2-\log_{\frac{1}{2}}2=\log_{\frac{1}{2}}3+2\log_{\frac{1}{2}}x-\log_{\frac{1}{2}}2.$

4. Use property

$\log_{a^k}b=\dfrac{1}{k}\log_ab.$

Then

$\log_{\frac{1}{2}}\left(\dfrac{3x^2}{2}\right)=\log_{\frac{1}{2}}3+2\log_{\frac{1}{2}}x-\log_{\frac{1}{2}}2=\log_{\frac{1}{2}}3+2\log_{\frac{1}{2}}x-\log_{2^{-1}}2=\\ \\=\log_{\frac{1}{2}}3+2\log_{\frac{1}{2}}x+\log_22=\log_{\frac{1}{2}}3+2\log_{\frac{1}{2}}x+1.$

Answer: correct option is B.

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4 years ago

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mezya [45]

Answer:

la Navidad

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la Nochebuena

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Step-by-step explanation:

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