Assuming you want us to simplify
remember
negative times negative=positive
and
remember the distributive proeprty
a(b+c)=ab+ac
and
-a(b+c)=-ab-ac
oh, and order of operations
so
-4(4/3v-4)-3(1/2v-4)
distribute
-4(-4/3v-4)=-4(-4/3v)-4(-4)=16/3v+16
-3(1/2v-4)=-3(1/2v)-3(-4)=-3/2v+12
so we now gots
16/3v+16-3/2v+12
group like terms
16/3v-3/2v+16+12
combine like terms
first the v terms
16/3v-3/2v=32/6v-9/6v=23/6v
then the constants
16+12=28
so we gets
23/6v+28 is the simlified form
Answer:
t=12
Step-by-step explanation:
t/3 - 2 = 2
3(t/3 - 2 = 2)
t - 6 = 6
t = 12
Answer:
Step-by-step explanation:
Answer:
Step-by-step explanation:
<u>Given equation:</u>
- .
- .
<u>Your answer will be Option D.</u>