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2 years ago

Why is the symbol for a piece of aluminum foil written as AI, when it actually contains billions of aluminum atoms?

Chemistry

1 answer:

lisov135 [29]2 years ago

6 0

Answer:

Read Explanation

Explanation:

Aluminum foil does contain billions of atoms, but we write them just as Al because aluminum does not exist in single atom forms in normal circumstances but as billions in metallic bonds.

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A sample of argon initially has a volume of 5.0 L and the pressure is 2 atm. If the final temperature is 30° C, the final volume

jenyasd209 [6]

Volume of Argon V1 = 5.0 L
Pressure of Argon P1 = 2 atm
Final temperature T2 = 30 C = 30 + 273 = 303 K
Volume at final temperature V2= 6 L
Pressure at final temperature P2 = 8 atm
We know that (P1 x V1) / T1 = (P2 x V2) / T2
(2 x 5)/ T1 = (8 x 6)/ 303 => T1 = (10 x 303) / 48
Initial Temperature T1 = 3030 / 48 = 63.12
Initial Temperature = -209. 8 C

4 0

2 years ago

How many 20.0-g ice cubes are required to absorb 47.0 kJ from a glass of water upon melting?

Sati [7]

Hello!

The number of 20-g ice cubes required to absorb 47 kJ from a glass of water upon melting is 7 icecubes

Why?

We are going to clear from the equation of the released heat, the mass of ice (m). The specific latent heat of fusion of ice is 336 kJ/kg:

$Q=m*L\\ \\ m=\frac{Q}{L}=\frac{47 kJ}{336 kJ/kg}=0,1399 kg=139,88 g\\ \\ 139,88g*\frac{1 icecube}{20g}=6,99=7icecubes$

So, 7 ice cubes are required to absorb that amount of heat from the glass of water.

Have a nice day!

3 0

2 years ago

Ira Lisetskai [31]

Answer:

$410mg/day *\frac{1000 ug}{1 mg}$

Recommended daily Amount (RDA) of magnesium is 410,000 μg/day.

Explanation:

There are 1000μg in 1 mg and 1000 mg in 1g

1 mg=1000μg

The Recommended daily Amount (RDA) is 410 mg/day of magnesium. Converting 410 mg/day into μg/day

$410mg/day *\frac{1000 ug}{1 mg}$

It will become 410,000 μg/day

So Recommended daily Amount (RDA) of magnesium is 410,000 μg/day.

4 0

3 years ago

It takes 2 g of chlorine to sanitize 1,000,000g of water. How much chlorine will it take to sanitize a 40,000-gallon pool? ( 1 g

dimulka [17.4K]

Answer:

0.1g (Gallon) of chlorine

Explanation:

Formula

1 gallon = 3.7L; the density of water is 1.0g/ml

Given

2g (gallon) of chlorine to sanitize = 1,000,000g (gallon) of water

Solve

If 2g (gallon) chlorine = 1,000,000g (gallon)

∴, ? chlorine = 40,000

The First step; set up an equation

1000000/2 = 40000/?

The Next step; divide 1 million to 2

1000000 ÷ 2 = 500000

Then, divide the result by 40000

40000 ÷ 500000 = 0.08

In the nearest unit that is 0.1

Therefore, it will take 0.1g (gallon) of chlorine to sanitize a 40,000-gallon pool.

7 0

2 years ago

Read 2 more answers

What is another way of describing a freezing point change?

Paladinen [302]

Melting is equivalent to freezing: a temperature when a solid become a liquid.

7 0

3 years ago

Read 2 more answers