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krok68 [10]
3 years ago
8

Which of the following chemicals is implicated in both global warming and ozone depletion?a. chlorofluorocarbons b. sulfur dioxi

de c. nicotine d. radon
Chemistry
1 answer:
Bingel [31]3 years ago
7 0

Answer:

A

Explanation:

Chlorofluorocarbons generally abbreviated as CFCs are a group of organic chemicals used in several household and industrial materials and are responsible for global warming and ozone depletion.

Global warming is the general increase in the atmospheric temperature of the earth continually over the years. It is a direct consequence of climate change which is caused by the continuous release of green house gases into the atmosphere which trap radiated heat from the sun.

Ozone depletion involves anthropogenic activities which lead to decreasing the natural spread of the ozone layer which prevents the direct contact between the sun UV radiation and the earth.

CFCs are implicated in both cases as they are responsible for the two I.e they cause global warming and also deplete the ozone layer. Years back they are basically used in most aerosol cans like perfumes spray, insecticide spray etc. However as a result of the increased knowledge of their dangers, there had been legislations which had cut down on their continuous usage with alternatives being used

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Select the statement (2.5 points) (A) Bonding is the joining of the two atoms in a stable arrangement. (B) Through bonding , ato
Tanya [424]

Answer:

The correct answer is (D) All of the above.

Explanation:

A chemical bond is the attraction force between atoms (covalent bond) or between oppositely charged ions (ionic bond) to form a stable arrangement. In order to get a stable arrangement must be fulfilled the octet rule. This establishes that an atom could share (covalent bond) win or lose (ionic bond) electrons with other atoms till every atom has eight valence electrons. The complete outer shell of valence electrons make elements stable to get a stable noble gas configuration.

6 0
3 years ago
Balance the following chemical equation I would give anyone the brainiest for answering.
serg [7]

<u>Answer :</u>

Part 13:

The balanced chemical reaction will be:

Cu(NO_3)_2+Na_2SO_4\rightarrow CuSO_4+2NaNO_3

Part 14:

The balanced chemical reaction will be:

Cu(NO_3)_2+Na_2C_2O_4\rightarrow CuC_2O_4+2NaNO_3

Part 15:

The balanced chemical reaction will be:

Cu(NO_3)_2+2KOH\rightarrow Cu(OH)_2+2KNO_3

<u>Explanation :</u>

Balanced chemical reaction : It is defined as the reaction in which an individual element of an atom present on reactant side must be equal to product side.

Part 13:

The balanced chemical reaction will be:

Cu(NO_3)_2+Na_2SO_4\rightarrow CuSO_4+2NaNO_3

Part 14:

The balanced chemical reaction will be:

Cu(NO_3)_2+Na_2C_2O_4\rightarrow CuC_2O_4+2NaNO_3

Part 15:

The balanced chemical reaction will be:

Cu(NO_3)_2+2KOH\rightarrow Cu(OH)_2+2KNO_3

5 0
3 years ago
Calculate the number of grams of sodium chloride in the solution. (Hint: Remember that sodium chloride is a strong electrolyte.)
creativ13 [48]

The question is incomplete, here is the complete question:

A solution contains 0.115 mol  H_2O and an unknown number of moles of sodium chloride. The vapor pressure of the solution at  30°C  is 25.7 torr. The vapor pressure of pure water at this temperature is 31.8 torr. Calculate the number of grams of sodium chloride in the solution. (Hint: Remember that sodium chloride is a strong electrolyte.)

<u>Answer:</u> The mass of sodium chloride in the solution is 0.714 grams

<u>Explanation:</u>

The formula for relative lowering of vapor pressure will be:

\frac{p^o-p_s}{p^o}=i\times \chi_{\text{solute}}

where,  

p^o = vapor pressure of solvent (water) = 31.8 torr

p^s = vapor pressure of the solution = 25.7 torr

i = Van't Hoff factor = 2

\chi_{\text{solute}} = mole fraction of solute (sodium chloride) = ?

Putting values in above equation, we get:

\frac{31.8-25.7}{31.8}=2\times \chi_{NaCl}\\\\\chi_{NaCl}=0.0959

Mole fraction of a substance is calculated by using the equation:

\chi_A=\frac{n_A}{n_A+n_B}

\chi_{\text{NaCl}}=\frac{n_{\text{NaCl}}}{n_{\text{NaCl}}+n_{\text{water}}}

We are given:

Moles of water = 0.115 moles

0.0959=\frac{n_{\text{NaCl}}}{n_{\text{NaCl}}+0.115}\\\\n_{\text{NaCl}}=0.0122mol

To calculate the mass for given number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

Moles of NaCl = 0.0122 moles

Molar mass of NaCl = 58.5 g/mol

Putting values in above equation, we get:

0.0122mol=\frac{\text{Mass of NaCl}}{58.5g/mol}\\\\\text{Mass of NaCl}(0.0122mol\times 58.5g/mol)=0.714g

Hence, the mass of sodium chloride in the solution is 0.714 grams

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Sergio [31]
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3 years ago
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Answer:

Determination to succeed.

Explanation:

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