Answer:
Cr₂O₇⁻²(aq) and ClO₃⁻(aq)
Explanation:
At a redox reaction, one substance must be reduced (gain electrons) and others must be oxidized (lose electrons). To evaluate the potential of the substance to be reduced, it's placed a reaction, in standards conditions, with H₂.
The potential reduction is quantified by E°, and as higher is the value of E°, as easy is to the compound to be reduced. So, at a redox reaction, the compound with the greatest E° will be reduced, and the other will be oxidized, in a spontaneous reaction. The values of E° are:
RuO₄⁻(aq) to RuO₄²⁻(aq) E° = + 0.59 V (the reduction reaction is the opposite of the oxidation reaction).
Ni⁺²(aq) E° = -0.257 V
I₂(s) E° = +0.535 V
Cr₂O₇⁻²(aq) E° = +1.33 V
ClO₃⁻(aq) E° = +0.890 V
Pb²⁺(aq) E° = -0.125 V
So, the substances that have E° higher than the E° of the RuO₄⁻²(aq) are Cr₂O₇⁻²(aq) and ClO₃⁻(aq), which are the substances that can oxidize RuO₄⁻(aq) to RuO₄²⁻(aq).
It can possible be you're arteries or also you're intestines with is large and small.
Answer:
2060.775 J
Explanation:
From the question given above, we obtained the following data:
Specific heat capacity (C) = 0.129 J/g°C
Mass (m) = 355 g
Initial temperature (Tᵢ) = 95 °C
Final temperature (Tբ) = 140 °C
Heat (Q) tranfered =?
We can calculate the amount of heat transferred by using the following formula:
Q = mC(Tբ – Tᵢ)
Q = 355 × 0.129 (140 – 95)
Q = 45.795 × 45
Q = 2060.775 J
Thus, 2060.775 J of energy was transferred.
Answer: 0.6159872299002939 or 0.61 or 0.615 I think please don't get mad if I got this wrong