Answer:
0.95 L
Explanation:
Step 1: Given data
Concentration of the Mg(NO₃)₂ solution (C): 0.32 M (0.32 mol/L)
Mass of Mg(NO₃)₂ (solute): 45 g
Step 2: Calculate the moles corresponding to 45 g of Mg(NO₃)₂
The molar mass of Mg(NO₃)₂ is 148.33 g/mol.
45 g Mg(NO₃)₂ × 1 mol Mg(NO₃)₂ /148.33 g Mg(NO₃)₂ = 0.303 mol Mg(NO₃)₂
Step 3: Calculate the volume of solution that contains 0.303 moles of Mg(NO₃)₂
The concentration of the solution is 0.32 M, that is, there are 0.32 moles of Mg(NO₃)₂ per liter of solution.
0.303 mol Mg(NO₃)₂ × 1 L Solution / 0.32 mol Mg(NO₃)₂ = 0.95 L
The answer is <span>B) the resulting compound cannot be dissolved in water. Ionic compounds are, in fact, very soluble in water. They are known to dissociate in aqueous solutions, producing ions or charged atoms. This makes aqueous solutions of ionic compounds good conductors of electricity. As solids, ionic compounds form salt crystals. They have high melting and boiling points due to the strong ionic bond that holds them.</span>
Pb (CO3)2 I’m assuming you just need to convert it to the formula.